#include #include #include int main() { char **Str; Str= (char**)calloc(20,sizeof(char)); Str[0]= (char*) calloc(10, sizeof(char)); Str[0]= "Hello, world"; printf("%s", *(Str+0)); } What I have...

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I am trying to sort some chars alphabetically to practice on sorting array

18 Feb 2023 by Addy__0

#include #include #include char **StringArray(char **arr, int size); int main() { char **Str; int n= 5; int i; Str= (char**)calloc(5,sizeof(char)); Str[0]= (char*) calloc(10, sizeof(char)); ...

I am trying to sort some chars alphabetically to practice on sorting array

17 Feb 2023 by CPallini

Quote: Str= (char**)calloc(5,sizeof(char)); That should beStr= (char**)calloc(5,sizeof(char *)); Might be there are other errors, as well. Anyway the code is not robust against user input.

I know that char** is a pointer to pointer to a char and char* is a pointer to char, but I cannot understand the difference?

20 Feb 2023 by Fred van Lieshout

Just keep in mind that everything takes up memory, including pointers. It can be handy to let a pointer (to a pointer) point to something else. Also, the line where memory is allocated to store the actual string, is not needed. Str[0]= (char*)...

I am trying to sort some chars alphabetically to practice on sorting array

18 Feb 2023 by merano99

Currently, this is C source code. The other programming languages according to the tag are irrelevant. There are several errors: // Str = (char**)calloc(5, sizeof(char)); need space for pointer, use n for size! Str = (char**)calloc(n,...

A History of C and C++ Character Data Types

25 Nov 2022 by Nemanja Trifunovic

Purpose, history and scenarios of use of character data types

I know that char** is a pointer to pointer to a char and char* is a pointer to char, but I cannot understand the difference?

17 Feb 2023 by OriginalGriff

You allocate a block of memory (20 chars worth) and tell the system that that is a set of pointers to chars - because Str is a pointer to a pointer to a char. Which is effectively a pointer to a string. Think of Str as a array of pointers to...

I am trying to sort some chars alphabetically to practice on sorting array

17 Feb 2023 by OriginalGriff

Probably because it doesn't compile: you declare StringArray as returning achar** - but the function body does not have a return statement. If code doesn't compile, then it doesn't generate an EXE file - so what you are running is the previous...

Converting between NSString and C Strings in an iOS Project

8 May 2023 by ToughDev