I need to display the employee who is living in more than one city

Question

1.40/5 (3 votes)

See more:

Find employee who is living in more than one city in the below two tables

EMP_TABLE
----------
EMPID
EMPNAME

CITY_TABLE
-----------
EMPID
PLACE

What I have tried:

I have lot of confusion in above query,please can anyone give me a solution for above one

Posted 12-Feb-17 20:59pm

Naresh S

Updated 16-Feb-17 9:05am

Add a Solution

Comments

Suvendu Shekhar Giri 13-Feb-17 3:03am

Share the incorrect query you have tried so far.

4 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Suvendu Shekhar Giri · Answer 1 · 2017-02-12T21:06:00

Solution 1

First of all, would recommend to try something before asking question in the forums.
You can try something like-

SQL

SELECT EMPID,EMPNAME,COUNT(PLACE) AS NoOfPlaces
FROM EMP_TABLE E
LEFT JOIN CITY_TABLE C ON E.EMPID=C.EMPID
GROUP BY EMPID,EMPNAME
HAVING COUNT(PLACE)>1

Hope, it helps :)

Posted 12-Feb-17 21:06pm

Suvendu Shekhar Giri

Comments

Naresh S 13-Feb-17 4:21am

tried to execute with below query

select a.empname from emp5 a left join city b on a.empid=b.empid where a.empid in(select empid from city )

Peter Leow · Answer 2 · 2017-02-12T21:54:00

Solution 2

Try this:

select * from emp_table e where exists ( select 1 from city_table c where c.empid=e.empid having count(*) > 1)

Posted 12-Feb-17 21:54pm

Peter Leow

Updated 12-Feb-17 22:01pm

v2

Naresh S · Answer 3 · 2017-02-12T23:46:00

Solution 3

select e.empname from emp5 e inner join city b  on e.empid=b.empid  where e.empid
 in(select empid from city group by empid having count(*)>1)

I have given for two different places one empid

Please correct me if i am wrong.

Posted 12-Feb-17 23:46pm

Naresh S

Naresh S · Answer 4 · 2017-02-16T09:05:00

Solution 4

select a.empname from emp5 a,city b where a.empid=b.empid group by a.empname having count(*)>1

Posted 16-Feb-17 9:05am

Naresh S