I need to display the employee who is living in more than one city

Question

1.40/5 (3 votes)

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Find employee who is living in more than one city in the below two tables

EMP_TABLE
----------
EMPID
EMPNAME

CITY_TABLE
-----------
EMPID
PLACE

What I have tried:

I have lot of confusion in above query,please can anyone give me a solution for above one

Posted 12-Feb-17 20:59pm

Naresh S

Updated 16-Feb-17 9:05am

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Comments

Suvendu Shekhar Giri 13-Feb-17 3:03am

Share the incorrect query you have tried so far.

4 solutions

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Naresh S · Answer 1 · 2017-02-16T09:05:00

Solution 4

select a.empname from emp5 a,city b where a.empid=b.empid group by a.empname having count(*)>1

Posted 16-Feb-17 9:05am

Naresh S

Naresh S · Answer 2 · 2017-02-12T23:46:00

Solution 3

select e.empname from emp5 e inner join city b  on e.empid=b.empid  where e.empid
 in(select empid from city group by empid having count(*)>1)

I have given for two different places one empid

Please correct me if i am wrong.

Posted 12-Feb-17 23:46pm

Naresh S

Peter Leow · Answer 3 · 2017-02-12T21:54:00

Solution 2

Try this:

select * from emp_table e where exists ( select 1 from city_table c where c.empid=e.empid having count(*) > 1)

Posted 12-Feb-17 21:54pm

Peter Leow

Updated 12-Feb-17 22:01pm

v2

Suvendu Shekhar Giri · Answer 4 · 2017-02-12T21:06:00

Solution 1

First of all, would recommend to try something before asking question in the forums.
You can try something like-

SQL

SELECT EMPID,EMPNAME,COUNT(PLACE) AS NoOfPlaces
FROM EMP_TABLE E
LEFT JOIN CITY_TABLE C ON E.EMPID=C.EMPID
GROUP BY EMPID,EMPNAME
HAVING COUNT(PLACE)>1

Hope, it helps :)

Posted 12-Feb-17 21:06pm

Suvendu Shekhar Giri

Comments

Naresh S 13-Feb-17 4:21am

tried to execute with below query

select a.empname from emp5 a left join city b on a.empid=b.empid where a.empid in(select empid from city )