How to open an exe file available in hard disk without go through the directory path

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I want to open the file name SymCorpUI.exe available in C drive but unable to execute the exe file directly without going through the whole directory path

What I have tried:

I use the code
Process.Start(My.Computer.FileSystem.CurrentDirectory & "\SymCorpUI.exe")

but it shows file not found

Posted 10-Oct-17 4:39am

Member 10616186

Updated 10-Oct-17 4:48am

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Richard MacCutchan 10-Oct-17 11:51am

You cannot. You must use the full path, unless the file is in the current working directory, or one of the directories listed in the PATH environment variable. And it is always much safer to use the full known path.

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OriginalGriff · Answer 1 · 2017-10-10T04:48:00

Solution 1

Start by looking at exactly what file path you are trying to open.

C#

Dim path as String = My.Computer.FileSystem.CurrentDirectory & "\SymCorpUI.exe"
Process.Start(path);

Put a breakpoint on the Process.Start line, and run your app in the debugger. When it hits, look at the content of path.
It should be the full path to the executable, so check that folder holds the file. If it doesn't, then you need to specify a different folder ...

Posted 10-Oct-17 4:48am

OriginalGriff

Comments

Member 10616186 10-Oct-17 11:11am

Sir, Still shows same error as SymCorpUI.exe file is available in path
C:\Program Files\Symantec\Symantec Endpoint Protection\Bin
but I want to run without specify the path

OriginalGriff 10-Oct-17 11:29am

Ah! The only way to run it without specifying the path is if it is in a location that Windows searches for executables. If you open a command prompt and type "path" it will show you where that is at present.

If it isn't in one of those folders, Windows won't find it and it won't get run without a path being specified.

Member 10616186 10-Oct-17 11:16am

while Debugging then path shows Nothing

Member 10616186 11-Oct-17 3:24am

Sir, I think we go with some alternate like firstly we access the full path of the Symantec File & then it appears on some label box then we call that label through Process. Start.

Currently I am not able to access the full path like file name- SymCorpUI.exe is available in "C:\Program Files\Symantec\Symantec Endpoint Protection\12.1.7061.6600.105\Bin" but how can we access the path or while form loading whether above path appeared