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For all global variables defined in the dll header, I defined a function (inside the dll) which returns the value/address of the corresponding global variable. These functions are called from the sample app instead of trying to access the global variables.
Now, the dll seems to work - I can render my pdf files.
Alex
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If you're passing arguments by reference to/from a dll, remember that the safest thing to do is to allocate/deallocate within the same binary. In another words, don't allocate something in the dll and try to deallocate it within the executable (or the other way around).
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Thank you for reminding that.
As far as I can see, this is already done right in the sample file.
Alex
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How can I declare a CString reference into a generic class ?
In fact, I want to declare a CString reference that could store errors, but that CString variable to be part of external class (let's say CMyWinApp class) ... it's ilogical request ?
I try to do :
CString& m_sErrorExt;
but I get follow error :
'm_sErrorExt' : must be initialized in constructor base/member initializer list
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Reference and const member variables must be given a value when initialized or in the constructor. Google for examples of how to resolve error C2758.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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You need to initialize it in the constructor.
class CMyClass
{
public:
CString m_DefaultErrorExt;
CString & m_sErrorExt;
public:
CMyClass(void) : sErrorExt(DefaultErrorExt) {}
CMyClass(CString & ExternError) : sErrorExt(ExternError) {}
};
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With this said, this can be a dangerous practice. If the object your object is linked to, goes out of scope, your code will crash when it tries to access the reference.
I don't use this technique often. In my code, my most common usage is when I'm working with legacy code that has really bad variable names. I'll sometimes create a new variable with a meaningful name, and convert the old one to a reference, so that it's still available to code I don't intend to touch.
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In my class, I do something that could throw into exceptions, so, I put an string reference in method paramter, like this :
BOOL CMyClass::Execute(LPCTSTR lpszParam1, CString& sError);
so, I give up the first request ... I don't know if is good ideea ...
thank you all anyway.
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I don't understand what you're saying there.
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Maybe it would help to understand what a reference[^] is.
Unrequited desire is character building. OriginalGriff
I'm sitting here giving you a standing ovation - Len Goodman
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The way you describe it, that string sounds like an object property - the last error message - so it's better and simpler to let it be a member of your class and add an accessor function for it...
class MyClass
{
public:
bool execute()
{
try
{
throw exception("Testing testing");
return true;
}
catch(exception& e)
{
m_lastError = e.what();
return false;
}
}
CString& lastError()
{
return m_lastError;
}
private:
CString m_lastError;
};
void tryIt()
{
MyClass c;
if( c.execute() )
cout << "All well" << endl;
else
cout << "MyClass.execute failed: " << c.lastError().GetString() << endl;
}
This is safer because you know the CString goes out of scope at the same time your class does, and you still have a CString reference available to use from the rest of your code exactly as before.
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Here is what I'm going to do :
CMyClass
{
BOOL Execute(LPCTSTR lpszSQL,CString& sError);
}
BOOL CMyClass::Execute(LPCTSTR lpszSQL,CString& sError)
{
try
{
throw ....
}
catch(CException* e)
{
e->GetErrorMessage(sError.GetBufer(255),255);
sError->ReleaseBuffer();
e->Delete();
}
}
somewhere, along 'Execute' method, might have an error, and want to have method feedback and error description in one code line :
CMyClass obj;
CString sError;
if(! obj.Execute(_T("SELECT * FROM mytable"),sError))
{
MessageBox(sError);
return;
}
which in fact, it's the same thing like you describe above ...
First time, I was thinking that I could setup an external CString reference to have all posible error in CMyClass, but now I see that is not the best idea ...
But, one for another, I learn something here because of you guys, and for that I will kindly thank you.
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Hi!
I've declared a a global structure and a static variable in a file called Common.h like this:
<pre lang="c++">
struct MenuSettings
{
int ScreenWidth;
int ScreenHeight;
}
static MenuSettings mSettings;
</pre>
I'm assigning values to ScreenWidth and ScreenHeight by reading a text file. This code is inside a file called Menu.cpp. While debugging the values of ScreenWidth and ScreenHeight inside Menu.cpp, the values are assigned correctly. I'm checking the following condition inside another file called Scroll.cpp:
<pre lang="c++">
if(mSettings.ScreenHeight >= 340)
{
}
</pre>
Here the value of "ScreenHeight" fetched from file is not coming. Instead it's coming as 0 and the if statement is bypassed. I need the correct value of ScreenHeight at Scroll.cpp. How to get it?
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You should define the variable in just one source file, for instance:
(1) remove
pix_programmer wrote: static MenuSettings mSettings; from the header file.
(2) Put, in the Menu.cpp file the variable definition:
MenuSettings mSettings;
(3) Put in Scroll.cpp file the variable declaration as extern :
extern MenuSettings mSettings;
That's all.
Veni, vidi, vici.
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'static', when applied to a variable definition, means you can't see the variable outside the scope of the file in which it's declared.
if you want to share a variable across CPP files, define the variable, in Menu.cpp, like this:
MenuSettings mSettings;
and then in Scroll.cpp, add the following declaration:
extern MenuSettings mSettings;
that tells the compiler to look in other files for the variable.
better yet, put extern MenuSettings mSettings; in a common header file. that way you can use the variable by simply #including the header.
also: global variables are generally not a good idea.
modified 17-Feb-12 8:35am.
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class Base
{
public:
Base() { }
virtual void foo1() { }
virtual void foo2() { }
} ;
class Derived : public Base
{
public:
Derived() { }
void foo1() { }
void foo3() { }
} ;
int _tmain(int argc, _TCHAR* argv[])
{
Derived * d = (Derived*)new Base() ;
d->foo3() ;
return 0;
}
In above code,
1) How it is possible to call foo3() of derived class.
2) If I call d->foo1(), Base class foo1() is getting called.
I am not able to understand this. Please explain.
Regards
msr
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d is initialized with the vtable of Base , that's the reason why Base::foo1 is called.
On the other hand it is declared as a pointer to a Derived object, hence the compiler (you fooled) calls the foo3 method.
Try
class Derived : public Base
{
int data;
public:
Derived() { data = 100;}
void foo1() { }
void foo3() { cout << data << endl;}
} ;
Too see why fooling the compiler is not a good idea.
Veni, vidi, vici.
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Hi, I have tried this. I am getting some junk value.
Why is this happened?
Regards
msr
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Because there is no instance of Derived , the method reads garbage.
Veni, vidi, vici.
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msr_codeproject wrote: 1) How it is possible to call foo3() of derived class.
Just like you have it. What's the problem?
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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OK, this is real simple.
You instantiate an instance of the "Base" class and then you fool the compiler into thinking it's a "Derived" class object.
Then you called a function that only exists in a "real" instantiation of a "Derived" class object.
What you did was fool yourself into expecting something reasonable to happen and you're surprised when it doesn't.
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msr_codeproject wrote: I am not able to understand this. Please explain.
In addition to the other replies...
Don't write code like that. It is bad code.
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Bad line here below. Don't do that.
Derived * d = (Derived*)new Base() ;
Try
Derived * d = new Derived;
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Quick Q. Trying to set mark parity, write some data, set space parity, write out some more data. Doing this to emulate a wakeup bit for an older serial protocol. Now I am not convinced that I can do it reliably.
Initially I tried using SetCommsMask followed by WriteFile. When this failed, I also tried DeviceIOControl using IOCTL_SERIAL_SET_LINE_CONTROL, but alas, same result (SetCommsMask uses this anyway). The parity bit is not always set. I am not using overlapped comms.
When I look at the standard serial port driver supplied with the WDK, I see that IOCTL_SERIAL_SET_LINE_CONTROL uses WdfInterruptSynchronize to set the Line Control Register, and from what I read this is not synchronous (ie waits for an interrupt), so possible means that the parity bit might not always be set in the UART before I write out the data. Is this correct, or am I barking up the wrong tree?
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Andrew Pearson wrote: the parity bit might not always be set in the UART before I write out the data. Very likely. The timing of access to UART control registers has ALWAYS been a horror.* Remember that there's a FIFO buffering your tx data.
Suggestion: Unless you're using 8 data bits + parity, you can do it yourself. Just use 'n+1' data length and set/unset an appropriate high order bit.
* Since the original WD1402 in 1972 or thereabouts. The 8250 and its 16xxx successors (as used in PCs) are not much better. You might get the wrong effect, but at least they don't hang if you write to them at the "wrong" time.
Cheers,
Peter
Software rusts. Simon Stephenson, ca 1994.
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