what is this means??=> Program received signal SIGSEGV, Segmentation fault. 0x00000001 in ?? ()

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At the Beginning of my code i wrote :

1.section .data
2.fileName db '/home/fateme/Desktop/text.txt',0
3.

& when debug it (set breakpoint at line3!!)
it says:=> Program received signal SIGSEGV, Segmentation fault.
0x00000001 in ?? ()

why this means????? \m/ (i kill my self because of this errors:D)
text.txt is on my desktop!!!

Posted 13-Jul-10 10:16am

fateme_teimouri

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Richard MacCutchan 14-Jul-10 4:59am

Maybe if you showed the code at line 3 (and beyond) and explained which instruction caused the SEGV we could offer some better suggestions.

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Sandeep Mewara · Accepted Answer · 2010-07-13T19:33:00

A segmentation fault occurs when a program attempts to access a memory location that it is not allowed to access, or attempts to access a memory location in a way that is not allowed (for example, attempting to write to a read-only location, or to overwrite part of the operating system).

On Unix-like operating systems, a signal called SIGSEGV is sent to a process that accesses an invalid memory address.

For some details on Segmentation Fault[^].

Try to put the text file in a folder in another drive and give access privileges.