Method must have a return type in C# Class

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1.18/5 (3 votes)

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I'm building a Global Hotkey class for my app and I'm getting this: "Method must have a return type".

This is the code that I am currently using(it is from http://www.dreamincode.net/forums/topic/180436-global-hotkeys/[^]

C#

class HotKeys
    {
        public GlobalHotkey(int modifier, Keys key, Form form) //GlobalHotkey is giving me the error given before
        {
            this.modifier = modifier;
            this.key = (int)key;
            this.hWnd = form.Handle;
            id = this.GetHashCode();

        }

        public static class Constants
        {
            //modifiers
            public const int NOMOD = 0x0000;
            public const int ALT = 0x0001;
            public const int CTRL = 0x0002;
            public const int SHIFT = 0x0004;
            public const int WIN = 0x0008;

            //window message id for hotkey
            public const int WM_HOTKEY_MSG_ID = 0x0312;
        }

        private int modifier;
        private int key;
        private IntPtr hWnd;
        private int id;

        [DllImport("user32.dll")]
        private static extern bool RegisterHotKey(IntPtr hWnd, int id, int fsModifiers, int vk);

        [DllImport("user32.dll")]
        private static extern bool UnregisterHotKey(IntPtr hWnd, int id);



        public override int GetHashCode()
        {
            return modifier ^ key ^ hWnd.ToInt32();
        }

        public bool Register()
        {
            return RegisterHotKey(hWnd, id, modifier, key);
        }

        public bool Unregister()
        {
            return UnregisterHotKey(hWnd, id);
        }
    }

Thanks in Advance - Cheers - CCB

Posted 9-Apr-15 15:21pm

ChrisCreateBoss

Updated 27-Dec-19 19:43pm

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3 solutions

Solution 2

In a method signature you must declare a return type e.g void, int, bool etc.
If you meant it to be a constructor it must have the same name as the class.

Posted 9-Apr-15 15:38pm

BacchusBeale

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Sergey Alexandrovich Kryukov · Accepted Answer · 2015-04-09T15:36:00

Solution 1

You method GlobalHotkey either need to become a constructor, but then its name it should have the same name as it class.

All other methods, non-constructors, need return types, even if it does not return anything, then it's void, for example, public static GlobalHotKey Create(/* ... */) (where GlobalHotKey is then name of some type), public void DoSomething(/* ... */), and the like.

—SA

Posted 9-Apr-15 15:36pm

Sergey Alexandrovich Kryukov

Comments

ChrisCreateBoss 9-Apr-15 21:38pm

Wow, I didn't take a look to that, Thanks again Sergey!!

Sergey Alexandrovich Kryukov 9-Apr-15 21:56pm

You are welcome.
—SA

Sergey Alexandrovich Kryukov · Accepted Answer · 2015-04-09T16:06:00

ChrisCreateBoss asked

Something more, the class is finished, I want now to use it in my project, the class is in the same solution of Form1, but I can't use "using Hotkeys", it looks like if the class does not exists.

This is not how using directive (not to be mixed up with using statement) is used. First of all, this is not more that shortcut. There are alias and regular namespace forms.

Say, your class full name is My.Namespace.Hot.HotKey. Then, you can shortcut this full name in usage if you use using:

C#

using My.Namespace.Hot;
// ...
Hotkey instance;

or

C#

using My.Namespace;
// ...
Hot.Hotkey instance;

or

C#

using My;
// ...
Namespace.Hot.Hotkey instance;

or, finally alias:

C#

using VeryHot = My.Namespace.Hot.HotKey;
// ...
VeryHot instance;

In all cases, you can use the full names of the types, no matter is you use using or not.

I hope the examples are clear, but why not reading about it and learning both namespaces and using? Please see:
https://msdn.microsoft.com/en-us/library/z2kcy19k.aspx,
https://msdn.microsoft.com/en-us/library/0d941h9d.aspx,
https://msdn.microsoft.com/en-us/library/sf0df423.aspx.

—SA