How I Can Get Item For Top Menu Form Xml File

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Hello,
I have file Topmenu.xml like

XML

<?xml version="1.0" encoding="utf-8" ?>
<items>
  <item Text="Home" NavigateUrl="#templatemo-Home" />
  <item Text="Products" NavigateUrl="#templatemo-Products"  />
  <item Text="Downloads" NavigateUrl="#templatemo-Downloads"  />
  <item Text="Blog" NavigateUrl="#templatemo-blog"  />
</items>

And i want pull it on my webpage like:

HTML

<li><a href="#templatemo-Home">Home</a></li>
<li><a href="#templatemo-Products">Products</a></li>
<li><a href="#templatemo-Downloads">Downloads</a></li>
<li><a href="#templatemo-blog">Blog</a></li>

I think it maybe like:

C#

@foreach (var item in item_from_xmlFile)
{
  <li><a href="item.NavigateUrl">item.Name</a></li>
}

I using ASP.NET MVC Razor.

How i can do it.

Sorry, my english very bad!

Posted 5-Dec-14 5:09am

GinCanhViet

Updated 5-Dec-14 5:10am

v2

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SrikantSahu · Accepted Answer · 2014-12-05T06:31:00

Hi,
You can have a method in your page which can return you the list elements.
I have put them in Page_load.
----------------For Webforms-------------

C#

protected void Page_Load(object sender, EventArgs e)
    {
       
        XmlDocument doc = new XmlDocument();
        doc.Load(Server.MapPath("XMLFile.xml"));
        Console.WriteLine(doc.OuterXml);
        var rootNode = doc.DocumentElement;
        string list = string.Empty;
        for (int i = 0; i < rootNode.ChildNodes.Count; i++)
        {
            var node = rootNode.ChildNodes[i];
           list += "<li><a href=\"" + new ListItem(node.Attributes[0].Value) + "\">" + node.Attributes[1].Value + "</a></li>";
        }

        Response.Write(list);
    }

---------------------For MVC--------------------------

C#

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using System.Xml;

namespace MvcApplication1.Controllers
{
    public class HomeController : Controller
    {
        public ActionResult Index()
        {
            
            return View();
        }

        public ActionResult GetMenu()
        {
            XmlDocument doc = new XmlDocument();
            doc.Load(Server.MapPath("XMLFile.xml"));
            var rootNode = doc.DocumentElement;
            string list = string.Empty;
            Dictionary<string, string> menu = new Dictionary<string, string>();
            for (int i = 0; i < rootNode.ChildNodes.Count; i++)
            {
                var node = rootNode.ChildNodes[i];
                menu.Add(node.Attributes[0].Value, node.Attributes[1].Value);
            }
            return PartialView(menu);
        }

    }
}

---Partial view (GetMenu.cshtml)--

C#

@model Dictionary<string, string>
@foreach (var node in Model)
{
    <li><a href="@node.Key"> + @node.Value</a></li>
}

--Index.cshtml (for home controller)

Razor

@{
    ViewBag.Title = "Index";
}
<h2>Index</h2>
@Html.Action("GetMenu", "Home")

Thanks
Srikant