how to add two hexadecimal numbers in Assembley?

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Hi,
can any one please help me that how to write a program that prompts the user to enter two hexadecimal numbers from 0 to FFFF digits each, and print their sum on the next line in hexadecimal. If the user enters an illegal character, he or she should be prompted to begin again. Each input ends with a carriage return. i wanna know how to add check so that if user enter other than hexadecimal numbers he/she should be prompted about wrong digit.
thanx.

Posted 5-Dec-14 2:58am

Hamza Javed

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Richard MacCutchan · Accepted Answer · 2014-12-05T03:26:00

Solution 1

I already answered a similar question for you, at how to add two binary numbers in Assembly language?[^]. You can easily adapt that code to accept hex rather than binary. And printing a hex number character by character is not too difficult if you think about what to do for values greater than 9.

Posted 5-Dec-14 3:26am

Richard MacCutchan

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Hamza Javed 5-Dec-14 9:45am

Hmmmmmmmm
ok i will. Thanks :)