having error in getpackagefullname msdn given example

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In if condition argc value will be 1 whenever i do debug but control is not going for loop condition.

example link:
http://msdn.microsoft.com/en-us/library/windows/desktop/hh446605(v=vs.85).aspx[^]

Posted 7-Nov-14 22:34pm

I.P.Katti

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Richard MacCutchan · Answer 1 · 2014-11-07T23:41:00

Solution 1

You already asked this question at Facing error 87 in Getpackagefullname API (MSDN)[^]. Please do not repost, if you have additional information then please edit your original question.

You could start by providing the information that I repeatedly asked you for.

Posted 7-Nov-14 23:41pm

Richard MacCutchan

Jochen Arndt · Answer 2 · 2014-11-08T21:32:00

I think you refer to this part of the example code:

C++

if (argc <= 1)
    return ShowUsage();
for (int i=1; i<argc;>

If you would know the meaning of the C main function arguments, you would not ask this question. argc is the number of arguments passed on the command line and provided in argv where the first argument argv[0] is the name of the program if known or an empty string. So argc will be always at least 1.

If you want argc to be greater than 1 do what ShowUsage prints out:
Pass one or more additional command line arguments (PID numbers for the example program).