how many times this loop executes

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hi i want to calculate the order of below code . but my problem is that i don't know how many times the loop executes in worse case?
can any one tell me that how many times this loop execute?
thanks

C++

while(n>0)
{
r=n%m;
n=m;
m=r;
}

Posted 17-Oct-14 0:41am

sara74

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OriginalGriff · Answer 1 · 2014-10-17T01:50:00

Solution 1

Nobody can tell you: it's dependent on the input values.
If n == 0, it will run 0 times.
if n == 1000 and m == 10, it will fail with a divide by zero exception on the second pass.

We can't tell you a worse case for code that fails! :laugh:

Posted 17-Oct-14 1:50am

OriginalGriff

Comments

CPallini 17-Oct-14 8:06am

There is no division in the OP code.

OriginalGriff 17-Oct-14 8:17am

*cough*
r=n%m;
*cough*

Technically, it's a remainder, but it throws divide-by-zero errors if you try 10 % 0 for example. Probably because it's often implemented with a divide!

CPallini 17-Oct-14 8:28am

Yes, I've deleted my post.

CPallini · Answer 2 · 2014-10-17T02:05:00

Solution 2

Quote:
can any one tell me that how many times this loop execute?

On lucky scenarios, the following function tells you:

C

int how_many_times(int n, int m)
{
  int count = 0:
  while(n>0)
  {
    r=n%m;
    n=m;
    m=r;
    ++count;
  }
  return count;
}

Posted 17-Oct-14 2:05am

CPallini