Image not showing on Web Browser which I created in PHP

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I am using XAMPP to serve php pages. All my PHP codes are running fine. But when I create image using the following php code :

XML

<!DOCTYPE html>
<html>

<head>

</head>

<body>

<?php
$myImage = imagecreate( 200, 100 );
$myGray = imagecolorallocate( $myImage, 204, 204, 204 );
$myBlack = imagecolorallocate( $myImage, 0, 0, 0 );
imageline( $myImage, 15, 35, 120, 60, $myBlack );
header( "Content-type: image/png" );
imagepng( $myImage );
imagedestroy( $myImage );
?>

</body>
</html>

and run the page the Google Chrome and Firefox show just an image place holder and IE8 shows the following binary code:

<!DOCTYPE html>
<html>

<head>

</head>

<body>

‰PNG

IHDRÈdùHíHPLTEÌÌÌÓ33dMIDATH‰c`£`Àx§”
Nf*k²Ã)Ãø§”•5}À)ÅS†ÚšpJUà”a§²¦œ2ÔŽw<špj‚q0>
†;
uTBúŸIEND®B`‚
</body>
</html>

I have checked php.ini file and have removed ';" from before "extension=php_gd2.dll". Still not working. Please help.

Posted 19-Aug-14 6:28am

Madhukar Krishna

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Comments

Sergey Alexandrovich Kryukov 19-Aug-14 15:35pm

Aren't you drawing black line on black background? Your gray color is not used anywhere.
And use imagecreatetruecolor() instead.
—SA

Mohibur Rashid 19-Aug-14 22:19pm

The code is right. I already checked. draws black line on gray background. But the mistake is, he is also putting html data with image data. And sending header request after sending data output. I have already written, in detail, in answer section.

Sergey Alexandrovich Kryukov 19-Aug-14 22:55pm

Ah, great! Some bugs don't even come to mind. Well-spotted.
—SA

1 solution

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Mohibur Rashid · Accepted Answer · 2014-08-19T16:17:00

Here is few thing you need to understand about PHP and HTTP protocol.
According to HTTP protocol header must have to be sent by the server first.

php treats its header and data in two ways:
1. php gether all data and header seperately and store it memory. After the end of execution php will send the header and then data
2. PHP will start to send data right away from the beginning of the execution.

In most case the servers are configured as no 2.

So, what you did here is first you put html code. then in the middle you are sending header. Before php send the first byte out it sends out all its header. That is, before php sends out "" php already send out the header. So, no matter how many header you set afterward they will not be effected. Now your case what is happening is even worse. First you are sending out some html text and then telling the parser that its an image. Even if you do the right thing i.e. first sending the header and then sending out data, it will still suffer. The reason is, you are still sending invalid data, your html texts, for your image. The right code would be

PHP

<?php
$myImage = imagecreate( 200, 100 );
$myGray = imagecolorallocate( $myImage, 204, 204, 204 );
$myBlack = imagecolorallocate( $myImage, 0, 0, 0 );
imageline( $myImage, 15, 35, 120, 60, $myBlack );
header( "Content-type: image/png" );
imagepng( $myImage );
imagedestroy( $myImage );

That is it. Make sure there is no other data before <?php and no data after ?>. it would be way better if you do not use ?>