Jquery Datepicker in ascending order

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Hi.

I have two input text like

HTML

<input id="txtDT1" type="text" class="pdate" />
<input id="txtDT2" type="text" class="pdate" />

I am using datepicker on both of them.

eg

JavaScript

$('#txtDT1').datepicker({
            minDate: 0, changeMonth: true, changeYear: true, dateFormat: "mm/dd/yy"
        });


$('#txtDT2').datepicker({
            minDate: 0, changeMonth: true, changeYear: true, dateFormat: "mm/dd/yy"
        });

Now the problem is that in txtDT2, I have to set minDate property as selected on txtDT1. Please help.

Posted 2-Aug-14 2:32am

ujju.1

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Peter Leow · Answer 1 · 2014-08-02T08:57:00

Try this:

<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.10.4/themes/smoothness/jquery-ui.css" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.10.4/jquery-ui.min.js"></script></script>
 <script>
$(document).ready(function(){
    $( "#datepicker1" ).datepicker({         
        onClose: function() {
            var date2 = $('#datepicker1').datepicker('getDate'); 
            $( "#datepicker2").datepicker("setDate", date2).datepicker('option', 'minDate', date2);
        }
    });
    $( "#datepicker2" ).datepicker();
});
</script>
</head>
<body>
<p>Date1: <input type="text" id="datepicker1"></p>
<p>Date2: <input type="text" id="datepicker2"></p>
</body>
</html>