Working with Math.Round

Question

4.04/5 (4 votes)

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Hi Geeks,

Just a small doubt,

result=210900

C#

double value = Convert.ToDouble(result / 10000);

C#

value=21.0 
I need to get 21.09

How to get this?

Thanks

Posted 30-Jul-14 20:20pm

Sriram Ramachandran

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Philippe Mori 2-Aug-14 9:09am

You have to learn primitive types rules... In C/C++/C#, 201900 / 10000 is an integer division.

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Raul Iloc · Accepted Answer · 2014-07-30T20:41:00

1.When both operands are integer the results will be computed as integer (so without any decimals), then the final result will be converted to double.

2.The solution is to use variable of type double and then you could use Math.Round() in order to get as many decimal you wanted like in the next example:

C#

double value = Math.Round(result / 10000.0, 2);

CPallini · Accepted Answer · 2014-07-30T20:28:00

Solution 1

This way

C#

int result = 210900;
double value = result / 10000.0;

Posted 30-Jul-14 20:28pm

CPallini

Comments

Sriram Ramachandran 31-Jul-14 2:29am

Thanks.. It worked. But how this is working??? Why 10000.0??

CPallini 31-Jul-14 2:34am

10000.0 is a double constant. It forces the promotion of result to double before the division operator is applied.

Raul Iloc 31-Jul-14 2:34am

When both operands are integer the results will be computed as integer (so without any decimals), then the final result will be converted to double.

Rakesh Meel · Accepted Answer · 2014-07-30T20:31:00

Solution 2

visit here...

valuue =Math.Round(Convert.ToDouble(result/10000)),2);

C# Math.Round(double,Int32) Troubles
or

http://msdn.microsoft.com/en-us/library/system.math.round%28v=vs.110%29.aspx?cs-save-lang=1&cs-lang=csharp#code-snippet-11[^]

Posted 30-Jul-14 20:31pm

Rakesh Meel

Updated 30-Jul-14 20:33pm

v2

Comments

Philippe Mori 2-Aug-14 9:01am

Your example suffer the samme problem as OP example.

Working with Math.Round

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Solution 3

Solution 1

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