Read certificat from Usb

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hi to all,
I am creating an application for authentication Token and my problem is to read the certificate from usb .
Please if Any body is having any idea about it ; reply as early as possible.
Thank you in advance.

Posted 5-May-10 12:38pm

Maurinho0

Updated 6-Feb-23 18:15pm

Ankur^\m/

v2

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AspDotNetDev 5-May-10 21:17pm

Repost: http://www.codeproject.com/Messages/3462887/Read-certificate-from-USB.aspx

4 solutions

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Christian Graus · Answer 1 · 2010-05-05T12:59:00

Solution 1

If you're using ASP.NET, you obviously have no access to the file system on the users computer.

Posted 5-May-10 12:59pm

Christian Graus

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Member 12179018 22-Jun-16 17:16pm

Hi excuse me why you say that it no access to other computer ? It's posible create a kind of service to do it ?

Goutam Patra · Answer 2 · 2010-05-05T20:28:00

Solution 2

When you install the certificate from smart token it will install in your personal store or any store. Read the certificate from your personal store as usual and the token will be validated automatically.

Posted 5-May-10 20:28pm

Goutam Patra

Comments

Member 12179018 22-Jun-16 17:19pm

Hi, are there a way to get a certificate without the need to install it in certificate store ?

taztazon · Answer 3 · 2010-05-06T03:28:00

Solution 3

hello.
i think that there's a difference between reading certificate from store and reading it from smart token, those 2 ways are so different.
:))

Posted 6-May-10 3:28am

taztazon

Comments

Goutam Patra 17-May-10 8:07am

Nope not at all

Member 12179018 22-Jun-16 17:23pm

hi there, i'm looking a way to just read a certificate from usb token, can you explain me how can i do it ? thanks in advance

Member 15916289 · Answer 4 · 2023-02-06T18:15:00

Solution 4

To read the certificate from the USB token you need the vendor's APIs. However, to avoid this, when a USB eToken is plugged into the PC, the certificate is automatically copied to your personal store and thus can find it and use it

Posted 6-Feb-23 18:15pm

Member 15916289

Comments

Richard Deeming 7-Feb-23 4:12am

As already explained in solution 2, posted THIRTEEN YEARS AGO!