How to expire an application/demo after x days?

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Dear Sirs,
I am beginner in C++ and have problem with one my program.
I am C++ dll for protection my Expert advisor(Metatrader software).
I want make demo version for my client and want using time limit on that.
For example each client able use this software for 7 days and after that not workable for him/her.
I want simple code that check this time for me.
I am using win32 console.
Thanks.

/Edit M - Crossposting in forum[^]

Posted 5-May-10 6:10am

Rezame

Updated 5-May-10 6:33am

Moak

v3

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2 solutions

Solution 2

Dear Sir,
Thank you for your email.
You can find my source code in below.
I make with this source dll and dll will connect to another software for do something for me.
I want add one code to this that after Xdays not send signal to my other program.

#define WIN32_LEAN_AND_MEAN  // Exclude rarely-used stuff from Windows headers
#include <windows.h>
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
//----
#define MT4_EXPFUNC __declspec(dllexport)
/

//+------------------------------------------------------------------+
//|                                                                  |
//+------------------------------------------------------------------+
 int Len = 14;
double ld_0;
   double ld_8;
   double ld_16;
   double ld_24;
   double ld_32;
   double ld_40;
   double ld_48;
   double ld_56;
   double ld_64;
   double ld_72;
   double ld_80;
   double ld_88;
   double ld_96;
   double ld_104;
   double ld_112;
   double ld_120;
   double ld_128;
   double ld_136;
   double ld_144;
   double ld_152;
   double ld_160;
   double ld_168;
   double ld_176;
   double ld_184;
   double ld_192;
   double ld_200;
   double ld_208;
   
MT4_EXPFUNC double __stdcall Sig(double Ba,int ld_216,double Hi,double Lo,double Clo)
  {
	   
	 for (int li_224 = ld_216; li_224 >= 0; li_224--) {
      if (ld_8 == 0.0) {
         ld_8 = 1.0;
         ld_16 = 0.0;
         if (Len - 1 >= 5) ld_0 = Len - 1.0;
         else ld_0 = 5.0;
         ld_80 = 100.0 * ((Hi + Lo + Clo) / 3.0);
         ld_96 = 3.0 / (Len + 2.0);
         ld_104 = 1.0 - ld_96;
      } else {
         if (ld_0 <= ld_8) ld_8 = ld_0 + 1.0;
         else ld_8 += 1.0;
         ld_88 = ld_80;
         ld_80 = 100.0 * ((Hi + Lo + Clo) / 3.0);
         ld_32 = ld_80 - ld_88;
         ld_112 = ld_104 * ld_112 + ld_96 * ld_32;
         ld_120 = ld_96 * ld_112 + ld_104 * ld_120;
         ld_40 = 1.5 * ld_112 - ld_120 / 2.0;
         ld_128 = ld_104 * ld_128 + ld_96 * ld_40;
         ld_208 = ld_96 * ld_128 + ld_104 * ld_208;
         ld_48 = 1.5 * ld_128 - ld_208 / 2.0;
         ld_136 = ld_104 * ld_136 + ld_96 * ld_48;
         ld_152 = ld_96 * ld_136 + ld_104 * ld_152;
         ld_56 = 1.5 * ld_136 - ld_152 / 2.0;
         ld_160 = ld_104 * ld_160 + ld_96 * fabs(ld_32);
         ld_168 = ld_96 * ld_160 + ld_104 * ld_168;
         ld_64 = 1.5 * ld_160 - ld_168 / 2.0;
         ld_176 = ld_104 * ld_176 + ld_96 * ld_64;
         ld_184 = ld_96 * ld_176 + ld_104 * ld_184;
         ld_144 = 1.5 * ld_176 - ld_184 / 2.0;
         ld_192 = ld_104 * ld_192 + ld_96 * ld_144;
         ld_200 = ld_96 * ld_192 + ld_104 * ld_200;
         ld_72 = 1.5 * ld_192 - ld_200 / 2.0;
         if (ld_0 >= ld_8 && ld_80 != ld_88) ld_16 = 1.0;
         if (ld_0 == ld_8 && ld_16 == 0.0) ld_8 = 0.0;
      }
      if (ld_0 < ld_8 && ld_72 > 0.0000000001) {
         ld_24 = 50.0 * (ld_56 / ld_72 + 1.0);
         if (ld_24 > 100.0) ld_24 = 100.0;
         if (ld_24 < 0.0) ld_24 = 0.0;
      } else ld_24 = 50.0;
      return(ld_24);
   }
  
  }

Thanks.

Posted 5-May-10 7:47am

Rezame

Updated 5-May-10 8:05am

v2

Comments

Tarakeshwar Reddy 5-May-10 14:07pm

When ever you add code, use the

 tags or just select your code and click on the code block button. It makes it easier to read the code

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DaveAuld · Accepted Answer · 2010-05-05T07:35:00

There are different ways to achieve this

1) encrypted license files that contains the expiry dates etc.
2) encrypted license keys held in the registry
3) challenge/response mechanism which require an internet connection
4) probably others.......

Nobody is just going to give you a solution...you come up with the code, and if you get stuck then come and ask specifics.