Display Popup window in Right-Hand Corner of the Screen

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Hi!

how to display popup window at the right hand side of the screen.
Sample Code:

C#

function ShowCallSummary()
			{
			    var program = "<%= hidFkProgramGlCode.ClientID.ToString()%>"; 
				var phase = '<%= hidPhaseNo.ClientID %>';
				var agent = '<%= hidAgentGlCode.ClientID %>';
				
				var myWindow = window.self;
				var WinSettings = "center:no; resizable:no; dialogHeight:190px; dialogWidth:120px; edge:Raised; help:No; status:No;"
				var programCode = document.getElementById(program).value;
				var phaseNo = document.getElementById(phase).value;
				var agentCode = document.getElementById(agent).value;
				var myArg = new Array(programCode, phaseNo, agentCode);
				window.showModalDialog("CallSummary.aspx?program=" + programCode + "&phase=" + phaseNo + "&agent=" + agentCode, myWindow, WinSettings);
			}

Pls reply me as soon as possible.

Thanks & Regards,
Minal Shah.

Posted 29-Apr-10 20:11pm

shah.minal

Updated 29-Apr-10 20:20pm

Sandeep Mewara

v3

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Sandeep Mewara · Accepted Answer · 2010-04-29T20:25:00

You need to use:
dialogLeft:sXPos
Sets the left position of the dialog window relative to the upper-left corner of the desktop.
dialogTop:sYPos
Sets the top position of the dialog window relative to the upper-left corner of the desktop

Read here for more details:
http://msdn.microsoft.com/en-us/library/ms536759(VS.85).aspx[^]

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