libphonenumber convert a string to phoneNumber without region code

Question

1.00/5 (1 vote)

See more:

i'm using the below:

C#

bool isSuccess = false;
        PhoneNumberUtil phoneUtil = PhoneNumberUtil.GetInstance();

      PhoneNumber numberProto = phoneUtil.Parse(phoneNumber, "");
      var regionCode = phoneUtil.GetRegionCodeForNumber(numberProto);


      bool isValid = phoneUtil.IsValidNumber(numberProto);

      var cc = phoneUtil.GetCountryCodeForRegion(regionCode);
        var number = phoneUtil.ParseAndKeepRawInput(phoneNumber, regionCode);


        var b = phoneUtil.GetNumberType(number);

        if (b == PhoneNumberType.MOBILE)
        {
           isSuccess= true;
        }

my problem is that i have only a phone number as a string... i don't have a region code neither a country code and i need to convert the string number to type phoneNumber, i can't use the function Parse because it needs a region code...

any ideas how can i do that?

Posted 16-May-14 3:12am

Jocelyne El Khoury

Add a Solution

Comments

ZurdoDev 16-May-14 9:37am

Where are you stuck? It sounds like you are using some class I have never heard of, PhoneNumberUtil. Is this a google thing? If so, I would start by asking there.

KaushalJB 16-May-14 9:40am

Jocelyne did u try using
Convert.Tostring() or Convert.ToInt32() ?

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Ashok19r91d · Accepted Answer · 2014-05-16T23:04:00

Solution 1

Just append your contry code with Phone Number while parsing...
I'm not sure of your class "PhoneNumberUtil", But It's a Simple trick which I hope to be work good.

Try using like this.

PhoneNumber numberProto = phoneUtil.Parse("+91" + phoneNumber, "");

Posted 16-May-14 23:04pm

Ashok19r91d