How to implement in out parameter in c#

Question

0.00/5 (No votes)

See more:

How can we implement in out parameter in C#.

I know how to use an out parameter in C#. But I want something that I wanna pass a value in the out parameter . The value will be used in the function I called and then I will change the value of the parameter in the function which has to be reflected back to the callee.

I hope ref can be used for this. Was there is any other thing that I can use for this.. ?

Posted 10-Apr-14 16:54pm

Prasaad SJ

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Guruprasad.K.Basavaraju · Accepted Answer · 2014-04-10T17:02:00

Pass by ref is your answer..

C#

public static DataTable GetAddressData(string sprocName, string inputXML, ref string message)
      {
          //make a call to DB get your datatable
          message = "success";
          return dataTable;
      }

Calling it this way

C#

addressData = AvData.GetAddressData(sprocGet, getXML, ref messge);

Sergey Alexandrovich Kryukov · Accepted Answer · 2014-04-10T19:35:00

In addition to Solution 1. You can also use out parameter to pass an initial value to it, even though this form of parameter passing is not intended for such use. Both ref and out the by-reference mechanism of parameter passing. The difference is: out parameters are designed for output, so the compiler won't enforce initialization of such parameter before the call. From the other hand, the compiler will enforce assignment of some value to the out parameter before return.

In contrast to that, ref parameter must be initialized before call. From the other hand, the method implementation does not have to assign anything to this parameter.

Essentially, "in-out" parameter is ref.

—SA