Xml Serialization Is There Any Trick For Reference Problem in C#?

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C#

XML

serialization

Hi everyone,
I tried convert from an object to xml file. There is parent-child relation in object like below. I convert it, no problem. Is there another way or any trick better than my solution(in Load Function of Parent Class)?, because I will convert a graph to xml file. Maybe, I will face the same problem for edges. How can I solve reference problem?

 public class FileService<T>
{
    public void Save(T obj, string filePath)
    {
        XmlSerializer serializer = new XmlSerializer(typeof(T));
        TextWriter writer = new StreamWriter(filePath);
        serializer.Serialize(writer, obj);
        writer.Close();
    }

    public T Load(string filePath)
    {
        XmlSerializer serializer = new XmlSerializer(typeof(T));
        TextReader reader = new StreamReader(filePath);
        var obj = (T)serializer.Deserialize(reader);
        reader.Close();
        return obj;
    }
}

public class Parent
{
    List<Child> children;

    [XmlArray("Children")]
    [XmlArrayItem("Child")]
    public List<Child> Children
    {
        get
        {
            if (children == null)
                children = new List<Child>();
            return children;
        }
        set { children = value; }
    }


    public void AddChild(Child child)
    {
        child.Parent = this;
        Children.Add(child);
    }

    public static Parent Load(string path)
    {
        FileService<Parent> fileService = new FileService<Parent>();
        var parent = fileService.Load(path);
        parent.Children.ForEach(child => child.Parent = parent);
        return parent;
    }
}

public class Child
{
    int value;
    Parent parent;

    [XmlIgnore]
    public Parent Parent
    {
        get { return parent; }
        set { parent = value; }
    }

    [XmlElement("Value")]
    public int Value
    {
        get
        {
            return this.value;
        }
        set { this.value = value; }
    }

    public Child()
    {

    }

    public Child(int value)
    {
        this.value = value;
    }
}