question about group by query

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Hello I am doing one project in that i have to find the total number of customer order
i write the query following

SQL

SELECT tbl_customer.*, tbl_order.*, tbl_order_status.*, tbl_item.* ,count(tbl_order.order_id)
FROM tbl_order INNER JOIN tbl_item ON tbl_order.item_id = tbl_item.item_id INNER JOIN tbl_order_status ON tbl_order.order_id = tbl_order_status.order_id INNER JOIN tbl_customer ON tbl_order.customer_id = tbl_customer.customerid
  group by tbl_customer.customerid

but when I run that query I got following eror

It does not contain aggregate function or group by clause

Plz provide me solustionas fast as possible because I have to submit the project

provide me possible if example

Posted 31-Dec-13 9:08am

An@mik@

Updated 31-Dec-13 15:15pm

Nelek

v5

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Zoltán Zörgő 31-Dec-13 15:25pm

Tag mismatch. You should add sql instead of html.

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Christian Graus · Answer 1 · 2013-12-31T11:01:00

The other way around it is, use a CTE to group a unique identifier and the data being grouped, then join it in.

SQL

with grouping as 
(
  select customer_id, count(order_id) as orderCount from tbl_order group by customer_id 
)


SELECT tbl_customer.*, tbl_order.*, tbl_order_status.*, tbl_item.* , grouping.orderCount
FROM tbl_order INNER JOIN
tbl_item ON tbl_order.item_id = tbl_item.item_id INNER JOIN
tbl_order_status ON tbl_order.order_id = tbl_order_status.order_id INNER JOIN
tbl_customer ON tbl_order.customer_id = tbl_customer.customerid
inner join grouping on tbl_order.order_id = grouping.order_id
group by tbl_customer.customerid

My signature block links to my articles on SQL, the third is on how CTEs work.

**Zoltán Zörgő** · Answer 2 · 2013-12-31T09:30:00

Usig grouping requires following a simple rule: what's not in aggregate, has to be in group by clause. So if you use so many table.* in the projection part you need to include all hose fields in the group by clause. Which makes no much sense. So I suggest to restrict the number of fields displayed, and include those that are not in an aggregation (every one not in the count).

question about group by query

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