disply separate cluster

Question

0.00/5 (No votes)

See more:

i am working on image processing project in that i can divide image into three different cluster by sing k-means clustering algorithm.i want to separate each cluster or display each cluster separately or differentiate between cluster how can do that please suggest me how can i do that thaks in advance .

Posted 28-Nov-13 0:25am

baliram bhande

Updated 28-Nov-13 0:46am

v2

Add a Solution

Comments

phil.o 28-Nov-13 7:42am

What have you tried?

baliram bhande 28-Nov-13 8:44am

i have tried to getting pixel differentiate in image means i am getting white pixel and black pixel separate from the image .but my problem is that
my image is -http://puu.sh/5vLh8.png
in above image can be divide into three different cluster .i want to Extract only roads from that image .in above image when i getting only black pixel at that time road can be extract but other portion can be display. i want extract only roads like
-http://puu.sh/5vLso.jpg if u r wish to see code then no problem i will show my code or put in comment box thanks for asking

baliram bhande 30-Nov-13 5:26am

please give me suggestion what i do ?

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)