Set parent form of UITypeEditor

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I've implemented a custom UITypeEditor. The UITypeEditor is a modal dialog and should open as a child dialog of my application.
I've overriden the method EditValue, so i can show the dialog. The WindowsFormsEditorService handles the display of the dialog while in design time:

C#

public override object EditValue(ITypeDescriptorContext context, IServiceProvider provider, object value)
{
    if (context != null && context.Instance != null && provider != null)
    {
        this.context = context;
        edSvc = (IWindowsFormsEditorService)provider.
                 GetService(typeof(IWindowsFormsEditorService));
        if (edSvc != null)
        {
            CollectionEditorForm editorFrm = new 
                                CollectionEditorForm(newCollection);
            edSvc.ShowDialog(editorFrm);
        }
    }
}

I've tried to set the Owner-property of the editor form, but hadn't any success yet.
How can i set the owner of my editor form?

Thanks in advance

Posted 25-Nov-13 22:26pm

akamper

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TnTinMn 26-Nov-13 22:41pm

I am not understanding what your goal is.

"The UITypeEditor is a modal dialog and should open as a child dialog of my application."

Do you mean that you what to display editorFrm while the application is running?

akamper 27-Nov-13 3:27am

My project is a Dialog-Designer, like the one in VisualStudio.
The properties of the controls are configurable through a property grid.
Some of these properties are using an UITypeEditor for configuration and in some cases the UITypeEditor is a modal dialog (editorFrm).
The Dialog-Designer should be the owner of this modal dialog. At the moment my problem is that the modal dialog is opened at the wrong position.

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