Assembly Language Fusing

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I am trying to fuse an accepted 4-digit number, so far I have done the 2-digit number and got confuse fusing a 4-digit. Please help

Here my code:

ASM

mov ah,01
    int 21h
    sub al,30h
    mov bh,al

    mov ah,01
    int 21h
    sub al,30h
    mov bl,al

    call fuseIt

ASM

fuseIt PROC NEAR
    mov al,bh
    mov ah,0
    mov bl,10
    mul bl
    add al,bl
    RET
fuseIt ENDP

Posted 24-Sep-13 17:39pm

timJosh

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Sergey Alexandrovich Kryukov 25-Sep-13 0:26am

Excuse for my ignorance, what does "fusing" mean?
—SA

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Richard MacCutchan · Accepted Answer · 2013-09-24T21:58:00

You need to create a loop and save the intermediate value each time. My assembler is extremely rusty (so there are probably some obvious mistakes) but I would think something like:

ASM

total: dw 0 ; a zeroised word

    xor ax,ax
    move total,ax     ; set total to zero
    mov cx,4          ; repeat 4 times
loop:
    mov ax,total      ; get the total
    mov bx,10       
    mul bx            ; multiply by 10
    mov total,ax      ; save new total
    mov ah,01
    int 21h           ; get next character
    sub al,30h        ; make it a digit. NB need to check in range 0 to 9.
    xor ah,ah         ; make it 16 bits
    add total,ax      ; add it to the total
    dec cx            ; decrement the counter
    jg  loop          ; repeat 4 times