why my model will pass null?

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hello
why my model will pass null?
username , Tell,Mobil ,... will not fill in controller .they are my model's fields(Hiddenfor).
when i make alert in script block , i see them correctly.
but will not pass to controller.
i think ViewModelX in controller is diffrent to jsonMyModel in script block.
how can i make a relation between them?

JavaScript

<script type="text/javascript">

    $("#submit-btn2").click(function () {saveMyModel(); });

    function saveMyModel() {

        var e = document.getElementById("id_Send");
        var str = e.options[e.selectedIndex].value;

        var e2 = document.getElementById("id_Receive");
        var str2 = e.options[e.selectedIndex].value;


        alert(str);
        alert(str2);

        alert($(".tdRecievername").html());
       alert($(".tdMobile ").html());



        $.ajax({
            url: '@Url.Action("Save", "Home")',
            type: 'POST',
            contentType: 'application/json',
            data: JSON.stringify({
                jsonMyModel: {

                    username: $(".tdBuyername").html(),
                    Tell: $(".tdPhone").html(),
                    Name: $(".tdRecievername").html(),
                    Mobil: $(".tdMobile").html(),
                    Lname: $(".tdLname").html(),
                    ShFactor: $("#Sh-Factor").html(),
                    Address: $(".tdAddress").html(),
                    Cod: $(".tdPobox").html(),
                    id_send: str,
                    id_Receive:str2,
                    
                },
                success: function (data) {
                    alert('im back');
                    alert(data);
                },
                error: function (xhr, ajaxOptions, error) {
                    alert(xhr.status);
                    alert('Error: ' + xhr.responseText);
                }
            }),


        });


            }

</script>

Controller:

C#

[HttpPost]
        public ActionResult save(ViewModelX jsonMyModel)
        {
            var data = true  ;
            if (ModelState.IsValid)
            {

                result = HelperClass.Insert(jsonMyModel.Address, jsonMyModel.Cod,
                       jsonMyModel.ShFactor, jsonMyModel. id_send,
                      jsonMyModel.idNoePardakht_sefaresh, jsonMyModel.id_Receive, jsonMyModel.Lname, jsonMyModel.Mobil, jsonMyModel.Name, jsonMyModel.Tell, jsonMyModel.username);

               

            }
            else
            {
                data = false;



            }

            return Json(data);

        }

Posted 9-Sep-13 8:36am

Member 8454063

Updated 12-Sep-13 1:15am

v3

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Pooja Dhanani · Answer 1 · 2013-09-11T01:26:00

Solution 1

try to pass Ajax data as jQuery('#FormId').serialize()

Posted 11-Sep-13 1:26am

Pooja Dhanani

Comments

Member 8454063 12-Sep-13 7:16am

Pooja Dhanani thanks , is it possible you see my updated question?

Pooja Dhanani · Answer 2 · 2013-09-12T01:46:00

Solution 2

Post your data using Ajax request like

JavaScript

<pre lang="Javascript">
  $.ajax({
            url: "@Url.Action("Check", "Home")",
            type: "POST",
            data: {
                Name: $('.class1').html(),
                Email: $('.class2').html(),
                Mobile: $('.class3').html()
            },
            error: function () { alert('Error'); },
            successs: function (data) { alert('successs'); }
        });

MVC use JsonModelBinder to bind your model.No need to use Json.stringfy({jsonMyModel: {}})

Posted 12-Sep-13 1:46am

Pooja Dhanani

Comments

Member 8454063 12-Sep-13 10:33am

no it dose not work . i changed all code . put just one field . alert(xhr.status); is executed and shows 0 . so i changed code to below. now, althoghe dose not show Error and 0, but wil pass username null to controller like before .

function saveMyModel() {
var url = '@Url.Action("Save", "Home")';
$.post(url, {
username: ‘jack’
}, function (data) {
if (data)
alert("ok");
else
alert("Error ");

});
}