how to insert the value from begning

Question

4.00/5 (1 vote)

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Hi,

I have one table difference

Checkin
Checkout

now i have to execute this two query ....

SQL

INSERT   INTO difference(CHECKIN) SELECT checktime from checkinout where sensorid='1'
INSERT   INTO difference(CHECKOUT) SELECT checktime from checkinout where sensorid='2'

After executing the first query record look like.

Checkin Checkout
--------- ---------
8/19/2013 14:53 Null
8/19/2013 16:46 Null

and when i execute the second querry it look like..

VB

Checkin       Checkout
 ---------       ---------
8/19/2013 14:53  Null
8/19/2013 16:46  Null
NULL             8/19/2013 15:53
Null             8/19/2013 16:53

but i want it to be like this...

VB

Checkin       Checkout
 ---------       ---------
8/19/2013 14:53   8/19/2013 15:53
8/19/2013 16:46   8/19/2013 16:53

..

plz help...

Posted 25-Aug-13 21:06pm

Nawab Ahmad

Updated 25-Aug-13 23:19pm

Herman<T>.Instance

v2

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Aarti Meswania · Answer 1 · 2013-08-25T21:23:00

check this example

SQL

DECLARE @checkinout TABLE(in_time DATETIME, out_time DATETIME, senerio_id INT, u_id INT)

INSERT INTO @checkinout
SELECT * FROM
(
    SELECT '2013-09-08 14:53' AS in_time, NULL AS out_time, 1 AS senerio_id, 1 AS u_id
    UNION ALL
    SELECT '2013-09-08 16:46' AS in_time, NULL AS out_time, 1 AS senerio_id, 2 AS u_id
    UNION ALL
    SELECT NULL AS in_time, '2013-09-08 15:53' AS out_time, 2 AS senerio_id, 1 AS u_id
    UNION ALL
    SELECT NULL AS in_time, '2013-09-08 16:53' AS out_time, 2 AS senerio_id, 2 AS u_id
) AS t

SELECT
    u_id,
    MAX(in_time) AS in_time,
    MAX(out_time) AS out_time,
    DATEDIFF(MI,MAX(in_time),
    MAX(out_time)) AS diffInMinute
FROM @checkinout
GROUP BY u_id

Happy Coding!
:)