GetModuleFileName and case sensitivity

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Hi Guys,
I am using GetModuleFileName API in my program. It returns me the name of my executable. However, I see that under different environments, it give me output like

-- Win XP
output: test.exe
-- Win 7
output: TEST.EXE

not sure why the API gives me different outputs. Please help.

Posted 23-Jul-13 23:05pm

vikramlinux

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Jochen Arndt · Answer 1 · 2013-07-24T00:49:00

From GetModuleFileName()[^] in the MSDN:

Quote:
The string returned will use the same format that was specified when the module was loaded. Therefore, the path can be a long or short file name, and can use the prefix "\\?\".

So it should be like on your disk when double clicking the file in the Explorer and as typed when using the command shell to start the program.

Another cite:

Quote:
If a DLL is loaded in two processes, its file name in one process may differ in case from its file name in the other process.

While this applies to DLL's it indicates that the case it not always the same.

So you should accept the behaviour and optionally get the real name from the disk using FindFirstFile().

Richard MacCutchan · Answer 2 · 2013-07-24T00:44:00

Solution 1

You already posted this question at http://www.codeproject.com/Messages/4619610/GetModuleFileName-and-case-sensitivity.aspx[^], and received some feedback. Please post in one forum only.

Posted 24-Jul-13 0:44am

Richard MacCutchan