C question

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C

Write a program that, beginning with the integer 1, finds the integers that are:
(a) evenly divisible by 3 or 4
(b) evenly divisible by 5 or 6
For each, print the integer and which of the two conditions apply (it could be both). The
program should keep going until you have found five integers that are evenly divisible by 5 or
6.
Sample Output:
3 is evenly divisible by 3 or 4
4 is evenly divisible by 3 or 4
5 is evenly divisible by 5 or 6
6 is evenly divisible by 3 or 4 and 5 or 6
8 is evenly divisible by 3 or 4
9 is evenly divisible by 3 or 4
10 is evenly divisible by 5 or 6
12 is evenly divisible by 3 or 4 and 5 or 6
15 is evenly divisible by 3 or 4 and 5 or 6

This is the code i have so far:

#include <stdio.h>
int main(void)
{
    int i=1;
    int b=1;
    while (i<=5)
    {
        if(b%3 == 0 || b%4==0)
        {
            if(b%5==0||b%6==0)
            {
                printf("%d is evenly divisible by 3 or 4 and 5 or 6\n", b);
            }
        else 
        {
            printf("%d is evenly divisible by 3 or 4\n", b);
            }
        }
        if(b%5 == 0 || b%6==0)
        {
            i++;
            printf("%d is evenly divisible by 5 or 6\n", b);
        }
        
        b++;
            
    }
}

Sorry wrong CODE
im close to getting the right solution but it prints too many 5,6 or 3,4 please tell me whats wrong with my code.