Change Value in XML-Document

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Hi,
how can I select and change the value "Entwicklung" (bold, unterline) in this XML in C#?
Thank you
Regards
Nicole

XML

<?xml version="1.0" encoding="utf-8"?>
<nlog xmlns="http://www.nlog-project.org/schemas/NLog.xsd"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <!-- Pfad zu log-Verzeichnis  -->
  <variable name="logDir"  value="${specialfolder:folder=ApplicationData}/BAMF/Maris/logs"/>
  <variable name="logFile" value="${shortdate}.log"/>
  <variable name="umgebung" value="Entwicklung"/>
</nlog>

Posted 29-Apr-13 9:02am

gpc44

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Kenneth Haugland · Answer 1 · 2013-04-29T09:16:00

You could use Xelement class to do that:
http://msdn.microsoft.com/en-us/library/system.xml.linq.xelement_methods.aspx[^]

As shown here using ReplaceWith:
http://stackoverflow.com/questions/5820143/how-can-i-update-replace-an-element-of-an-xelement-from-a-string[^]

XML

// input would be your edited XML, this is just sample data to illustrate
string input = @"<Artist Name=""Pink Floyd"">
  <BandMembers>
    <Member>Nick Mason</Member>
    <Member>Syd Barret</Member>
    <Member>David Gilmour</Member>
    <Member>Roger Waters</Member>
    <Member>Richard Wright</Member>
  </BandMembers>
  <Category>Favorite band of all time</Category>
</Artist>";

C#

var replacement = XElement.Parse(input);
var pinkFloyd = xml.Elements("Genre")
                   .Where(e => e.Attribute("Name").Value == "Rock")
                   .Elements("Artist")
                   .Single(e => e.Attribute("Name").Value == "Pink Floyd");

pinkFloyd.ReplaceWith(replacement);
Console.WriteLine(xml);

tar565 · Answer 2 · 2013-04-29T12:21:00

Solution 2

This needs to be cleaned up but you can access it as follows :

var keyvalues = from item in document.Descendants()
                select item;

var xAttribute = keyvalues.ElementAt(3).Attribute("value");
if (xAttribute != null)
{
    var configvalue = xAttribute.Value;
}

Posted 29-Apr-13 12:21pm

tar565

Updated 29-Apr-13 12:23pm

v2