Same problem found: Fatal error encountered attempting to read the resultset

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ASP.NET

MySQL

Sir during file uploading he given problem occure and i don't know how to sole this problem.
Fatal error encountered attempting to read the resultset.

        protected void btn_save(object sender, EventArgs e)
        {
            //MySqlConnection exclecon = new MySqlConnection("Server=Localhost;DataBase=password1;user=root;password=nectar");
            string path = FileUpload1.PostedFile.FileName;
            string ext = Path.GetExtension(path);
            string contenttype = string.Empty;
            if (!FileUpload1.HasFile)
            {

                ClientScript.RegisterStartupScript(Page.GetType(), "validation", "<script language='javascript'>alert('Please select a file')</script>");  //if file uploader has no file selected

            }
            else if (FileUpload1.HasFile)
            {
                try
                {
                    switch (ext)
                    {
                        case ".csv":

                            contenttype = "application/vnd.ms-excel";

                            break;
                    }
                    string year = ddlyear.SelectedItem.ToString();
                    string month = ddlmonth.SelectedItem.ToString();
                    MySqlConnection exclecon = new MySqlConnection("Server=Localhost;DataBase=password1;user=root;password=nectar");
                    string insquery = "INSERT INTO sla (month, year, contenttype) VALUES(@month, @year, @contenttype)";
                    string uploadQry = "LOAD DATA LOCAL  INFILE '" + path + "' INTO TABLE sla1 FIELDS TERMINATED  BY ',' LINES TERMINATED BY '\\n' IGNORE 1 LINES ";
                    MySqlCommand mycom = new MySqlCommand(insquery, exclecon);
                    mycom.Parameters.AddWithValue("@month", month);
                    mycom.Parameters.AddWithValue("@year", year);
                    mycom.Parameters.Add("@contenttype", MySqlDbType.VarChar).Value = contenttype;

                    MySqlCommand myCUpload = new MySqlCommand(uploadQry, exclecon);
                    exclecon.Open();
                    mycom.ExecuteNonQuery();
                    myCUpload.ExecuteNonQuery();

                    ClientScript.RegisterStartupScript(Page.GetType(), "validation", "<script language='javascript'>alert('File uploaded Successfully ')</script>");

                }

                catch (Exception ex)
                {
                    Label4.Text = "Error: " + ex.Message.ToString();

                }
            }
        }
    }
}