putting open file dialogue into a separate class

Question

1.00/5 (1 vote)

See more:

Hi.
I have a program and would like to make it neater by making some classes and just calling them from the main. Most of the things are button clicks though - openFileDialogue. Is it possible to do that and what would I pass the class?

thanks

Posted 22-Feb-13 6:27am

defunktlemon

Add a Solution

Comments

LokoLuke 22-Feb-13 12:32pm

Create the class, add a few methods to the class such as openFileDialogue. Then in main create an instance of your new class and call your methods.

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

LokoLuke · Answer 1 · 2013-02-22T06:35:00

Solution 1

Create the class, add a few methods to the class such as openFileDialogue. Then in main create an instance of your new class and call your methods.

C#

namespace myNamespace
{
    class myClass
    {
      public void openDialogue() { //Do Something } 

     }
}

Posted 22-Feb-13 6:35am

LokoLuke

David_Wimbley · Answer 2 · 2013-02-22T06:39:00

This is a user control i wrote to move open file dialogue out of my code.

Set properties to access the Filename, dirname, full path and various other bits of file info that may be useful.

C#

public partial class FileUploads : UserControl
{
    public string FileName { get; set; }
    public string DirectoryName { get; set; }
    public string FullPath { get; set; }
    public string Extension { get; set; }
    public string FileNameNoExt { get; set; }

    public FileUploads()
    {
        InitializeComponent();
    }

    private void btnBrowse_Click(object sender, EventArgs e)
    {
        openFileDialog1.Filter = "(*.GIF;*.JPG;*.JPEG;*.PDF;*.PNG;*.MP3;*.TIF;*.WAV;*.WMA)|*.GIF;*.JPG;*.JPEG;*.PDF;*.PNG;*.MP3;*.TIF;*.WAV;*.WMA";
        openFileDialog1.RestoreDirectory = true;

        if (openFileDialog1.ShowDialog() == DialogResult.OK)
        {
                txtFileName.Text = openFileDialog1.FileName;
                FileName = Path.GetFileName(openFileDialog1.FileName);
                FileNameNoExt = Path.GetFileNameWithoutExtension(openFileDialog1.FileName);
                DirectoryName = Path.GetDirectoryName(openFileDialog1.FileName);
                FullPath = Path.GetFullPath(openFileDialog1.FileName);
                Extension = Path.GetExtension(openFileDialog1.FileName);
        }
    }
}