Remove duplicates form shorted shorted array

Question

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JavaScript

var removeDuplicates = function (nums) {
  for (let i = nums.length- 1; i >= 2; i--)

    if (nums[i - 2] == nums[i]) nums.splice[i, 1];
};

Output

output  [1,1,1,2,2,3] 

expected   [1,1,2,2,3]

What I have tried:

My question is that its is the not a complex data but is not define i dont know ..
please solve this questions

Posted 8-Nov-23 20:37pm

Codes with Abhi

Updated 9-Nov-23 7:13am

Andre Oosthuizen

v2

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Member 15627495 9-Nov-23 3:13am

https://flexiple.com/javascript/find-duplicates-javascript-array

if you need few methods , read this page

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Richard Deeming · Answer 1 · 2023-11-08T22:38:00

It's not clear what problem you're having, but the simplest way to remove duplicates in JavaScript is to use a Set[^]:

JavaScript

const removeDuplicates = nums => [...new Set(nums)];

However, the title and function name don't match your expected output, which clearly has duplicates in it. And since you haven't given us the input you use to produce that expected output, we can't even begin to guess what you're actually trying to do.

Andre Oosthuizen · Answer 2 · 2023-11-09T07:24:00

Your problem in your code is the use of '[]' instead of using '()' -

JavaScript

//Example array with duplicates using your given expected output...
let nums = [1, 1, 1, 2, 2, 3];

var removeDuplicates = function(nums) {
  for (let i = nums.length - 1; i >= 2; i--)
    if (nums[i - 2] == nums[i]) nums.splice(i, 1); //Use () instead of []...
};

//Call the removeDuplicates function...
removeDuplicates(nums);

//Output your modified array...
console.log(nums);

//OUTPUT - [1, 1, 2, 2, 3]...

I have created a fiddle for you - Javascript remove duplicates in a set of numbers [^]

Remove duplicates form shorted shorted array

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