What is the difference between portc|=(1<<portc) and portc|=(portc<<1)?

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I have a conflict in portc will shifted with a value 1
and 1 will shifted with the value of portc

What I have tried:

i have tried in 7 segments and reverses problems

Posted 9-Jul-23 4:33am

Ahmed Khaled Jul2023

Updated 9-Jul-23 5:19am

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PIEBALDconsult 9-Jul-23 10:41am

42

Andre Oosthuizen 9-Jul-23 12:51pm

:)

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OriginalGriff · Accepted Answer · 2023-07-09T05:19:00

The left shift operator A << B moves the bits of operand A by B places to the left: it multiplies A by 2^B

For example if A is 4 (i.e. binary 00000100) and B is 3, then A << B will return 32 (or binary 0100000)

So your two instructions do very different things:
1 << portc returns a single bit set at a position determined by teh value of portc
portc << 1 multiplies the value of portc by two.

The rest is obvious: the A |= B operator performs a bitwise OR between A and B and assigns the result to A.

I think you need to work out exactly what you need the code to do, and work out how to do that, rather than just randomly swapping operands over! I'd start by finding out what portc is used for and what it actually contains: I suspect you are using it very wrongly - but without the code we can;t tell.