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Hello,
I am using XAMARIN FORM.
I Can read the file after take the picture.
I can see the file.FileName
But no parameters is passed to the WEB API.
I am completly lost, i really do not know whey
C#
private async void TakePhoto_Clicked(object sender, EventArgs e)
 {
     var file = await MediaPicker.CapturePhotoAsync();
     var content = new MultipartFormDataContent();
     content.Add(new StreamContent(await file.OpenReadAsync()), "file", file.FileName);
     string url = "https://10.0.2.2:7254/api/GetData/Upload/";
     client.BaseAddress = new Uri(url);       
     var response = await client.PostAsync("", content);
     if (response.IsSuccessStatusCode)
           
  }

Web API
[HttpPost]
[Route("Upload")]
public async Task<string> Upload(  List <IFormFile> files)    
{
    try
    {
        foreach (var formFile in files)
        {
           if (formFile.Length > 0)
           {
              var fileName =  formFile.FileName.Split('\\').LastOrDefault().Split('/').LastOrDefault();
              var filePath = Path.Combine(Directory.GetCurrentDirectory(), "imagenes", fileName);
                       
               using (var stream = System.IO.File.Create(filePath))
               {
                  await formFile.CopyToAsync(stream);
               }


What I have tried:

I had read notes here and other site
Posted
Comments
Member 15627495 5-Apr-23 2:46am    
the split() function divide an item to an Array.
it breaks a big string in subparts ( belonging to the choosen separator )


when you use 'lastorDefault', you select the last index of the retrieve Array.

and after the Path.combine() a 'void' field make this function in error.

the error comes from the line "var filename = ...."






to debug and find the error :
- check the value about "filename"
- rewrite the line "var filename= ".

when you have a faulty code :
- trace your vars
- check their values and types
Luis M. Rojas 5-Apr-23 11:02am    
Well, if you see these lines:
content.Add(new StreamContent(await file.OpenReadAsync()), "file", file.FileName);
string url = "https://10.0.2.2:7254/api/GetData/Upload/";
client.BaseAddress = new Uri(url);
var response = await client.PostAsync("", content);
In this line:
content.Add(new StreamContent(await file.OpenReadAsync()), "file", file.FileName);
I can read and see the file.FileName
But in the Web Api, in this line: public async Task<string> Upload( List <iformfile> files)
files do not recive any value, i mean: it is EMPLY,
How do i pass the value from the program and pass it to the web api.
I did what you said.
Thanks to all

1 solution

as you want to get the name.extension of the string you have :

Path.GetFileName Method (System.IO) | Microsoft Learn[^]

var filename = path.getfilename(formFile)
// to break the big string and get the filename and extension only
 
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