Sql syntax; check the manual that corresponds to your mariadb server version for the right syntax to use near '''' at line 1

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if (isset($_POST['submit'])){
$NAME2=$_POST['name2'];
$query="SELECT id, name, gener, yearofprodction, opinion FROM movie_info WHERE name=.'$NAME';";
$result=mysqli_query($conn,$query);
$resultcheck= mysqli_num_rows($result);
if ($resultcheck > 0 );
{
while ($row =mysqli_fetch_assoc($result)) {
echo 'Name :'.$row['name'].'
'.'Gener :'.
$row['gener'].'
'.'Year of prodction :'.
$row['yearofprodction'].'
'.'Your opinion :'
.$row['opinion'];
break;
}
}
}

What I have tried:

I maked a connection with database and shered it and it still tell there an error in the $query statment I need help

Posted 17-Feb-23 7:20am

renad1423

Updated 17-Feb-23 22:15pm

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Comments

Richard Deeming 20-Feb-23 6:15am

Your code is vulnerable to SQL Injection[^]. NEVER use string concatenation/interpolation to build a SQL query. ALWAYS use a parameterized query.

PHP: SQL Injection - Manual[^]

1 solution

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Richard MacCutchan · Answer 1 · 2023-02-17T22:15:00

Solution 1

You should remove the dot at name=.'$NAME'. Also you creatre the variable $NAME2, but in the SQL statement you use $NAME, which is not declared anywhere.

Posted 17-Feb-23 22:15pm

Richard MacCutchan