I am trying to split the array into given chunk size. I have came up with a solution but can this be made any more simpler.

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Given the array and chunkSize. I have to produce the desired output
array = [1,2,3,4,5]
chunkSize = 1
desired output [1] [2] [3] [4] [5]

What I have tried:

I have tried using IntStream

Java

public static List<int[]> chunk(int[] input, int chunkSize) {
        return IntStream.iterate(0, i -> i + chunkSize)
                .limit((long) Math.ceil((double) input.length / chunkSize))
                .mapToObj(j -> Arrays.copyOfRange(input, j, j + chunkSize > input.length ? input.length : j + chunkSize))
                .collect(Collectors.toList());//how to fix this line error on new
    }

The function call I am doing in main method as:
List<int[]> list = chunk(original, splitSize);
list.forEach(splitArray -> System.out.println(Arrays.toString(splitArray)));

Posted 11-Dec-22 6:33am

Vibhanshu 2022

Updated 11-Dec-22 17:33pm

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Sandeep Mewara · Answer 1 · 2022-12-11T17:33:00

There could be multiple ways to do it. If there is no issue of space, I would prefer Arrays.copyOfRange()

In it, the copyOfRange() creates a new array of the same type as the original array, and contains the items of the specified range of the original array into a new array.

Syntax:

Java

public static T[] copyOfRange(T[] original, int from, int to)

// original – the array from which a range is to be copied
// from – the initial index of the range to be copied, inclusive
// to – the final index of the range to be copied, exclusive

More details: Java.util.Arrays.copyOfRange() Method[^]

Example usage:

Java

int[] arr1 = new int[] {15, 10, 45, 55};
int chunk = 2; // provided as input
for(int i=0; i<arr1.length; i+=chunk){
    System.out.println(Arrays.toString(Arrays.copyOfRange(arr1, i, Math.min(arr1.length,i+chunk))));
}