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Hi,

How to send form-data using HttpWebRequest post method. Please check my code and advise me how to set request.ContentLength and pass formData to request.

for "x-www-form-urlencoded" content-type, I have used like.

Stream requestStream = request.GetRequestStream();
requestStream.Write(formData, 0, formData.Length);
requestStream.Close();


Thanks,
K.Ajay.

What I have tried:

HttpWebRequest request;
HttpWebResponse response;
string filePath = HttpContext.Current.Server.MapPath("~/Uploads/test.pdf");            
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;            
MultipartFormDataContent formData = new MultipartFormDataContent();

// document content
formData.Add(new StringContent("Document Info"), "document");

// attachment content
FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read);
formData.Add(new StreamContent(fileStream), "attachment");
            
// Create Request
request = (HttpWebRequest)WebRequest.Create(apiUrl);
request.KeepAlive = false;
request.Timeout = 180000;
request.Method = "POST";
request.ContentType = "application/form-data";
//request.ContentLength = ;
request.PreAuthenticate = true;
request.Accept = "application/json";

// Get Response
response = (HttpWebResponse)request.GetResponse();
Posted
Updated 24-Nov-22 4:08am

1 solution

HttpWebRequest is an extremely low-level API, so you have to build the multipart/form-data request yourself. There's an example of how to do that in this SO thread[^] - essentially:
C#
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
request.ContentType = "multipart/form-data; boundary=" + boundary;

using (Stream rs = request.GetRequestStream())
{
    rs.Write(boundarybytes, 0, boundarybytes.Length);
    string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n";
    string header = string.Format(headerTemplate, paramName, file, contentType);
    byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
    rs.Write(headerbytes, 0, headerbytes.Length);

    using (FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read))
    {
        byte[] buffer = new byte[4096];
        int bytesRead = 0;
        while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
        {
            rs.Write(buffer, 0, bytesRead);
        }
    }

    byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
    rs.Write(trailer, 0, trailer.Length);
}

However, since your code uses the MultipartFormDataContent type, you already have a reference to the HttpClient class, which makes it much easier to upload files.
C#
using (var client = new HttpClient())
using (var formData = new MultipartFormDataContent())
{
    formData.Add(new StringContent("Document Info"), "document");
    
    FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read);
    formData.Add(new StreamContent(fileStream), "attachment");
    
    using (var response = await client.PostAsync(apiUrl, formData))
    {
        response.EnsureSuccessStatusCode();
        // Read and process response.Content here...
    }
}
NB: Bear in mind that creating a new HttpClient for every request in a long-running application can cause problems; it's better to use the IHttpClientFactory service:
You're using HttpClient wrong and it is destabilizing your software | ASP.NET Monsters[^]
You're (probably still) using HttpClient wrong...[^]
Make HTTP requests using IHttpClientFactory in ASP.NET Core | Microsoft Learn[^]
 
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