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I have a List<dictionary<long,string>>(), and I know that some dictionaries in it are exactly the same. Does anyone know how to compare each dictionary to the other dictionaries in the list?

What I have tried:

I tried via:
var listComplete = listDictionary.Distinct().ToList();

but unfortunately it was without result.

I know that a list that contains dictionaries should probably not be made, but I would be happy if someone could give me advice on this.

I would appreciate any advice and tips.

Updated 10-Nov-22 0:10am

You'll need to write an equality comparer:
public sealed class DictionaryEqualityComparer<TKey, TValue> : IEqualityComparer<IDictionary<TKey, TValue>>
    private readonly IEqualityComparer<TValue> _valueComparer;
    public DictionaryEqualityComparer(IEqualityComparer<TValue> valueComparer = null)
        _valueComparer = valueComparer ?? EqualityComparer<TValue>.Default;
    public bool Equals(IDictionary<TKey, TValue> left, IDictionary<TKey, TValue> right)
        if (left is null) return right is null;
        if (right is null) return false;
        if (left.Count != right.Count) return false;
        foreach (KeyValuePair<TKey, TValue> pair in left)
            if (!right.TryGetValue(pair.Key, out var value)) return false;
            if (!_valueComparer.Equals(pair.Value, value)) return false;
        return true;
    public int GetHashCode(IDictionary<TKey, TValue> obj)
        // TODO: Improve the hashcode:
        return obj?.Count ?? 0;
You would then need to use that class in your Distinct call:
var equalityComparer = new DictionaryEqualityComparer<long, string>();
var listComplete = listDictionary.Distinct(equalityComparer).ToList();
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dejf111 10-Nov-22 6:39am    
Thank you so much!
Google is your friend: compare 2 dictionaries c# - Google Search[^]

Here is one example: How to compare two dictionaries in C#?[^]

There are many more examples.
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dejf111 10-Nov-22 5:29am    
I also found that, but I don't know how to take two dictionaries from the List (gradually to compare each with each)

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