Pls help I m new to C and I can t figure it out ....

Question

1.00/5 (1 vote)

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i have to print the sum of digits of a number

int main ()
{
    int num, sum = 0;
    scanf("%d" , &num);
    while(num!=0){
        sum += num % 10;
        num = num / 10;
    }
 
    printf("the sum of the digits is %d",sum);
 
    return 0;
}

i write this but is i have a negative number let s say -35 i need the result to be 8 and my program is printing -8..how can i solve this ?

What I have tried:

i can t figure it out i tried..........

Posted 7-Nov-22 7:14am

Bogdan Alexandru Oct2022

Updated 7-Nov-22 7:41am

v2

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jeron1 7-Nov-22 13:37pm

Maybe use the (absolute value) abs() function in your printf statement?

printf("Suma cifrelor este %d",abs(sum));

2 solutions

Solution 2

Convert input to an absolute value.

C++

int main ()
{
    int num, sum = 0;
    scanf("%d" , &num);
    num = abs(num);   // Convert to absolute value
    while(num!=0){
        sum += num % 10;
        num = num / 10;
    }
 
    printf("Suma cifrelor este %d",sum);
 
    return 0;
}

Posted 7-Nov-22 7:41am

Mike Hankey

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Rick York · Accepted Answer · 2022-11-07T07:37:00

If you want to ignore the negative sign then you can treat all numbers as being positive so one way to do that is to make any negative number be a positive one. Here's one way you can do that :

C

int main ()
{
    int num, sum = 0;
    scanf("%d" , &num);

    if( num < 0 )
        num *= -1;   // change a negative number to be positive

    while(num!=0){
        sum += num % 10;
        num = num / 10;
    }
 
    printf("Suma cifrelor este %d",sum);
 
    return 0;
}