How to find the index of specific date in Python

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I have a netCDF file with 2544 time step (daily, 06-08-2014 to 24-07-2021), I want to find the time step corresponding to the date 25-Aug-2018

What I have tried:

import netCDF4
from netCDF4 import num2date, date2num, date2index
import numpy as np

f=netCDF4.Dataset('/../t.cdf')
times=f.variables['time']
dates = num2date(times[:], times.units)
print(dates.index(datetime.dates(2018, 8, 25)))

Posted 6-Oct-22 21:08pm

Swetha sivakumar

Updated 6-Oct-22 22:30pm

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Richard MacCutchan 7-Oct-22 4:05am

And? What happens when you run this code?

Swetha sivakumar 7-Oct-22 4:10am

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'numpy.ndarray' object has no attribute 'index'

Richard MacCutchan 7-Oct-22 4:20am

That does not correspond to the code you have posted above.

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Richard MacCutchan · Answer 1 · 2022-10-06T22:30:00

Solution 1

As stated in the error message there is no index attribute. You most likely meant to use item. See numpy.ndarray — NumPy v1.23 Manual[^].

Posted 6-Oct-22 22:30pm

Richard MacCutchan

Comments

Maciej Los 10-Oct-22 16:08pm

5ed!

Richard MacCutchan 11-Oct-22 3:44am

Thanks.