How can I write a C program to calculate x-a till n times where x equal to x and a is an integer

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I made this program for x-a expression where a is the value that will be entered by the user now how can I print this program till n times?
My code:

#include<stdio.h>

 int main() {
 int a,n;
char x; 

printf("enter value of a \n",a);
scanf("%d",&a); 


printf("Value of x is x %c\n",x);
n=x-a;
printf("x-%d",a);


 return 0;



 }

What I have tried:

I have made a code to print x-a
This is for my semester project I'm basically designing Taylor series general form for all polynomial function

Posted 15-Jul-22 12:48pm

Asma 2022

Updated 15-Jul-22 19:23pm

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OriginalGriff · Answer 1 · 2022-07-15T18:29:00

You will need to add a loop - probably a for loop is best: C For Loop[^]

But I'd suggest you start by reading your homework question again carefully and trying to work out manually what you are expected to get as output - the question as stated here makes very little sense since x can never be unequal to itself.
That's like saying "where 6 is equal to 6"! It is always true, so it's irrelevant.