How to use count over partition with cte instead of using having ?

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I work on sql server 2017 i have issue i can't use count over partition instead of using having distinct

main statment i use

SELECT P.PartsFamilyID, P.PackageID, R.RoHSStatus 
    
 FROM Parts.ManufacturingData M WITH(NOLOCK)
 INNER JOIN Parts.Nop_Part P WITH(NOLOCK) ON P.PartID = M.PartID
 INNER JOIN Parts.ROHS R WITH(NOLOCK) ON R.ZPartID = P.PartID
 where packageId is not null
 GROUP BY P.PartsFamilyID, P.PackageID, R.RoHSStatus
 HAVING COUNT(DISTINCT M.LeadFinishPlatingID) > 1 OR COUNT(DISTINCT M.BaseMaterialID) > 1

i need exactly rewrite statment above using count over partition with cte

What I have tried:

with ctemanufacture as
(
)
select * into #test from rn1 > 1 or rn2>1
so please
How can i do that please ?

Posted 3-Apr-22 2:53am

ahmed_sa

Updated 5-Apr-22 8:13am

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Maciej Los · Answer 1 · 2022-04-05T08:13:00

Start by reading MSDN documentation: OVER Clause (Transact-SQL) - SQL Server | Microsoft Docs[^]

SQL

SELECT ...
FROM (
  SELECT P.PartsFamilyID, P.PackageID, R.RoHSStatus,
    COUNT(*) OVER(PARTITION BY M.LeadFinishPlatingID  ORDER BY ...) AS Cnt1, 
    COUNT(*) OVER(PARTITION BY M.BaseMaterialID ORDER BY ...) AS Cnt2
  FROM ...
) AS T
WHERE T.Cnt1>1 OR Cnt2>1

If you want to use CTE, plase read this: WITH common_table_expression (Transact-SQL) - SQL Server | Microsoft Docs[^]