How to do this function recursively?

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I have a dictionary like this where some of the values are "None" and others are keys in the same dictionary

group = {
    "Duties & Taxes": "Current Liabilities",
    "Excise": "Duties & Taxes",
    "Bank Accounts": "Current Assets",
    "Branch / Divisions": "None",
    "Capital Account": "None",
    "Cash-in-hand": "Current Assets",
    "Current Assets": "None",
    "Current Capital Account": "Capital Account",
    "Current Liabilities": "None",
    "CWIP": "None",
    "Deposits (Asset)": "Current Assets",
    "Direct Expenses": "None",
    "Direct Incomes": "None",
    "GST": "Duties & Taxes"
}

I want to replace all the values that are not "None" to something like this:

{
    "Duties & Taxes": "Current Liabilities",
    "Excise": "Current Liabilities",
    "Bank Accounts": "Current Assets",
    "Branch / Divisions": "None",
    "Capital Account": "None",
    "Cash-in-hand": "Current Assets",
    "Current Assets": "None",
    "Current Capital Account": "Capital Account",
    "Current Liabilities": "None",
    "CWIP": "None",
    "Deposits (Asset)": "Current Assets",
    "Direct Expenses": "None",
    "Direct Incomes": "None",
    "GST": "Current Liabilities"
}

What I have tried:

I was not able to do this recursively.
This is the code that works if the depth is less than 6.

def get_up(group):
    # print(group)
    if group_dict[group] == "None":
        return group
    if group_dict[group_dict[group]] == "None":
        return group_dict[group]
    if group_dict[group_dict[group_dict[group]]] == "None":
        return group_dict[group_dict[group]]
    if group_dict[group_dict[group_dict[group_dict[group]]]] == "None":
        return group_dict[group_dict[group_dict[group]]]
    if group_dict[group_dict[group_dict[group_dict[group_dict[group]]]]] == "None":
        return group_dict[group_dict[group_dict[group_dict[group]]]]
    if group_dict[group_dict[group_dict[group_dict[group_dict[group_dict[group]]]]]] == "None":
        return group_dict[group_dict[group_dict[group_dict[group_dict[group]]]]]
    else:
        return group_dict[group_dict[group_dict[group_dict[group_dict[group]]]]]

Posted 23-Feb-22 15:24pm

PoornaRecharla

Updated 23-Feb-22 22:35pm

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2 solutions

Solution 1

Don't understand why you want to do it recursively. Check below

Python

group = {
    "Duties & Taxes": "Current Liabilities",
    "Excise": "Duties & Taxes",
    "Bank Accounts": "Current Assets",
    "Branch / Divisions": "None",
    "Capital Account": "None",
    "Cash-in-hand": "Current Assets",
    "Current Assets": "None",
    "Current Capital Account": "Capital Account",
    "Current Liabilities": "None",
    "CWIP": "None",
    "Deposits (Asset)": "Current Assets",
    "Direct Expenses": "None",
    "Direct Incomes": "None",
    "GST": "Duties & Taxes"
}
group.update({ "Excise": "Current Liabilities", "GST": "Current Liabilities"})
print(group)

Posted 23-Feb-22 19:19pm

_Asif_

Comments

PoornaRecharla 24-Feb-22 6:13am

This is just a sample list. I have around 500 items and the data changes frequently.
So, I need to update it regularly in my program.

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Richard MacCutchan · Accepted Answer · 2022-02-23T22:35:00

Solution 2

Try this:

Python

for key, value in group.items():
    if value in group and group[value] != "None":
        group[key] = group[value]
print(group)

Posted 23-Feb-22 22:35pm

Richard MacCutchan

Comments

PoornaRecharla 24-Feb-22 6:28am

It is returning "None" for almost all the items.

Richard MacCutchan 24-Feb-22 6:48am

It works for me.

PoornaRecharla 24-Feb-22 7:21am

It works. Thank you.