How to make that code working?

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Visual-Studio

Python

I have to make the following working by using conditionals

# 1. arithmetic mean (INPUT:LIST)

def calc_mean(mylist):

# 2. harmonic_mean (INPUT:LIST)
def calc_harmonic_mean(mylist):

# 3. median (INPUT:LIST)

def calc_median(mylist):

# 4. low median (INPUT:LIST)
def calc_low_median(mylist):

# 5. high median (INPUT:LIST)
def calc_high_median(mylist):

# 6. mean(INPUT:DICTIONARY)
def calc_mean_dicts(mydict):



What I have tried:

I tried the following, but it didn't work. Is it a problem on the code syntax or the order of the code orders? How would look like otherwise?

import statistics
import numpy as np

def calc_mean(mylist):
    mylist=[1, 3, 4, 5, 7, 9, 2]
    x = statistics.calc_mean(mylist)
    print("Mean is :", x)

if __name__== '__main__':
    calc_mean()


def calc_harmonic_mean(mylist):
     mylist=[1, 3, 5, 7, 9]
     print("Harmonic Mean is % s " % (statistics.calc_harmonic_mean(mylist)))

if __name__== '__main__':
    calc_harmonic_mean()



def calc_median(mylist):
        mylist = [20, 2, 7, 1, 34]
        if mylist>8:
            print("arr : ", mylist) 
            print("median of arr : ", np.calc_median(mylist))

if __name__== '__main__':
    calc_median()
 
def calc_low_median(mylist):
    mylist = [1, 3, 3, 4, 5, 7]
    print("Low median of the data-set is % s " % (statistics.calc_low_median(mylist)))

if __name__== '__main__':
    calc_low_median()

def calc_high_median(mylist):
    mylist = [1, 3, 2, 8, 5, 4]
    print("High median of the data-set is %s "% (statistics.calc_high_median(mylist)))

if __name__== '__main__':
    calc_high_median()    


def calc_mean_dicts(mydict):
    mydict = {"Gfg" : 4, "is" : 7, "Best" : 8, "for" : 6, "Geeks" : 10}
    print("The original dictionary is : " + str(mydict))

if __name__== '__main__':
    calc_mean_dicts()