How can you subtract all elements in an array into a single result and store it in a variable?

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For example, I want

C++

int ar[2]{20, 5};

to be stored in a variable

C++

double result = 15;

What I have tried:

C++

for(int i = 0; i < 2; i++{
 result -= ar[i];
}

Posted 28-Oct-21 11:52am

apetrai

Updated 28-Oct-21 20:13pm

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jeron1 28-Oct-21 18:15pm

What is 'result' initialized to?

[no name] 28-Oct-21 23:48pm

If you want the results to be 15, then you need to use {-20,5}

2 solutions

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Rick York · Answer 1 · 2021-10-28T14:45:00

Besides the syntax errors, the only thing I see that is wrong with what you have is the types of the data do not agree. The array holds integers and the result is a double.

I try to avoid using literal values so I would define a constant value for the array size so your code could look something like this:

C++

const int ArraySize = 2;

int data[ArraySize] = { 20, 5 };
int result = 15;

for( int i = 0; i < ArraySize; ++i )
{
    result -= data[ i ];
}

CPallini · Answer 2 · 2021-10-28T20:13:00

Solution 2

Try also

C++

#include <iostream>
#include <array>
using namespace std;

int main()
{
  array<int,2> ar{20, 5};

  int result{15};

  for ( auto x : ar )
    result -= x;

  cout << "result = " << result << endl;
}

Posted 28-Oct-21 20:13pm

CPallini