What did I do wrong ? for dev C++

Question

1.00/5 (1 vote)

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[Error] expected identifier or '(' before '{'

What I have tried:

C++

#include <stdio.h>
int main ()
{
	printf("Welcome to Health is Wealth Co Customer's Data"); }
	
 char Q;
 {
 
    printf("Quit program");
    
    if (enter Q)

       printf("Thank you for using the system. Have a nice day\n");	
       
 
    char E()


	printf("Enter order\n");

	if (enter E)
	   
	
   	int quantity;
   	float price, SubtotalAmount;
   	printf("Enter quantity and price:");
	scanf("%d%f", &quantity * price);
	
	SubtotalAmount = quantity * price;
	printf("The subtotal amount is:\n% * RM %.2f\n", quantity, price, SubtotalAmount);
	return 0;
	
 }

Posted 19-May-21 15:17pm

angelsruto

Updated 19-May-21 20:09pm

Dave Kreskowiak

v3

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Dave Kreskowiak · Answer 1 · 2021-05-19T16:02:00

Solution 1

You REALLY need to go through your code and clean up the curly braces and parenthesis. They are screwed up and what is causing your problems. They MUST match up correctly.

Posted 19-May-21 16:02pm

Dave Kreskowiak

Updated 19-May-21 16:03pm

v2

KarstenK · Answer 2 · 2021-05-19T19:21:00

Solution 2

As Dave wrote you must clean up your code at first. In this effort most IDE like Visual Studio have some helping functions and shortcuts.

Writing clean code as primary task helps you to avoid such mess and concentrate on the features.

Posted 19-May-21 19:21pm

KarstenK

OriginalGriff · Answer 3 · 2021-05-19T20:09:00

As stated, sort out the braces and indentation: most IDEs will help you there, once you get the braces working.
But ... that code shows every sign of being thrown together without any thought or design effort being put into it, and that always a mistake.
These aren't valid C++:

if (enter Q)

Just rubbish!

C++

char E()

No semicolon

if (enter E)

More rubbish.Even if it was something sensible, the only code which would be executed if it evaluated to true is a single variable declaration - so it would immediately go out of scope anyway!

scanf("%d%f", &quantity * price);

Two fields, needs two output locations. What on earth does an address multiplied by any number mean? Think about address as mobile phone numbers: if I multiply your phone number by 3 and dial the result, who do I call?

printf("The subtotal amount is:\n% * RM %.2f\n", quantity, price, SubtotalAmount);

Two outputs specified, three provided.

That code says one thing to me: "I can't be bothered to learn and think about this subject". I'd strongly suggest you start with your course notes from the beginning again, and then start from scratch with this assignment - what you have there isn't worth saving!