Parse error syntax error, unexpected token "]", expecting "-" or identifier or variable or number on line 59

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if(empty($error)){
		$sql="SELECT*FROM user_d WHERE email = '".$
		$result= $conn->query($sql);
		$customer_data=array();
		if($result->num_rows > 0){
			$error[] = "Email already exist!";
		}
		else{
			$error=array();
			$sql="INSERT INTO
	user_d(`f_name`,`l_name`,`dob`,`email`,`password`);
	VALUES($fname,$lname,$dob,$email);
		if($conn->query($sql)===TRUE){
			$success[]= "Account created successfully";
		} else{
			$errors[] = "Error:".$sql."<br>".$conn->error;
		}
	}
}	
$_SESSION['error']=$error;
$_SESSION['success']=$success;
header("Location:register_customer.php');

What I have tried:

$success[]= "Account created successfully";
$success()= "Account created successfully";

Posted 9-May-21 13:51pm

Jazmin Ardis

Updated 9-May-21 17:29pm

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Patrice T · Answer 1 · 2021-05-09T17:29:00

PHP

$sql="SELECT*FROM user_d WHERE email = '".$
// Previous line is truncated

PHP

        $sql="INSERT INTO
user_d(`f_name`,`l_name`,`dob`,`email`,`password`);
VALUES($fname,$lname,$dob,$email);
// double quote is missing here  ^

Not a solution to your question, but another problem you have.
Never build an SQL query by concatenating strings. Sooner or later, you will do it with user inputs, and this opens door to a vulnerability named "SQL injection", it is dangerous for your database and error prone.
A single quote in a name and your program crash. If a user input a name like "Brian O'Conner" can crash your app, it is an SQL injection vulnerability, and the crash is the least of the problems, a malicious user input and it is promoted to SQL commands with all credentials.
SQL injection - Wikipedia[^]
SQL Injection[^]
SQL Injection Attacks by Example[^]
PHP: SQL Injection - Manual[^]
How can I explain SQL injection without technical jargon? - Information Security Stack Exchange[^]