Checking the double six in result of dice but not wokring.....

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The counter still appears "0" despite the appearance of double 66 in the result.
After that I want to check the result for longest sequence of successive rolls without six. but don't know how to get started. help please.

What I have tried:

<pre>from random import *

trial = int(randint(1, 70))
print(trial)
result = ''
for i in range(trial):
    init_num = str(randint(1, 6))
    result += init_num
print(result)

last_dice = 0
counter = 0
for i in range(trial):
    if result[i] == 6 and last_dice == 6:
        counter += 1
        last_dice = 0
    else:
        last_dice = result[i]

print(counter)

Posted 30-Apr-21 8:46am

Francis Sadiq

Updated 30-Apr-21 9:00am

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Richard MacCutchan 1-May-21 4:10am

I gave you a simple solution to this problem yesterday.

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Patrice T · Answer 1 · 2021-04-30T08:58:00

Quote:
The counter still appears "0" despite the appearance of double 66 in the result.

The trick is that new you made result a string, and that imply that you need to compare with strings.

Python

<pre>from random import *

trial = int(randint(1, 70))
print(trial)
result = ''
for i in range(trial):
    init_num = str(randint(1, 6))
    result += init_num
print(result)

last_dice = "0" # change to string
counter = 0
for i in range(trial):
    if result[i] == "6" and last_dice == "6": # change to string
        counter += 1
        last_dice = "0" # change to string
    else:
        last_dice = result[i]

print(counter)

OriginalGriff · Answer 2 · 2021-04-30T09:00:00

result is a total, not an array of values: if it was an array, then your total display wouldn't work:

Python

for i in range(trial):
    init_num = str(randint(1, 6))
    result += init_num
print(result)

So, you can't assume that you will have the previous set of values stored in it!

Think about it: why do you have two loops at all? Could you do it with no array and just one loop?
Hint: "yes" :D

Checking the double six in result of dice but not wokring.....

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