How to fix PHP parse error: syntax error, unexpected '$_SERVER' (T_VARIABLE) ?

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when i try to run my php script i got this error HP Parse error:  syntax error, unexpected '$_SERVER' (T_VARIABLE) on line 7 ,here is the code :
<?php
  ob_start();
echo "<p><center>wait one second</center></p>" ;
echo "Using header() function" ;
header("Location: https://zoom.us") ;
$file = fopen("data.txt","a") ;
$ip=$_SERVER['REMOTE_ADDR'] $_SERVER["REMOTE_ADDR"] : '127.0.0.1';
$browser = $_SERVER['HTTP_USER_AGENT'] ;
echo fwrite ($file,$ip) ;

 ob_end_flush();

?>

What I have tried:

i dont know how to fix it, the code :

<?php
  ob_start();
echo "<p><center>wait one second</center></p>" ;
echo "Using header() function" ;
header("Location: https://zoom.us") ;
$file = fopen("data.txt","a") ;
$ip=$_SERVER['REMOTE_ADDR'] $_SERVER["REMOTE_ADDR"] : '127.0.0.1';
$browser = $_SERVER['HTTP_USER_AGENT'] ;
echo fwrite ($file,$ip) ;

 ob_end_flush();
?>

Posted 16-Apr-21 12:49pm

yzyoussefzack656

Updated 16-Apr-21 17:12pm

v2

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Patrice T · Accepted Answer · 2021-04-16T17:12:00

Quote:
syntax error, unexpected '$_SERVER' (T_VARIABLE) on line 7

This means that

PHP

$ip=$_SERVER['REMOTE_ADDR'] $_SERVER["REMOTE_ADDR"] : '127.0.0.1';
                           ^ at this point, you code is not php any more.

Solution depends on what you intend to di there.
Just a guess: Did you tried to use the ternary operator ?
In this case, correction is

PHP

$ip=$_SERVER['REMOTE_ADDR'] ? $_SERVER["REMOTE_ADDR"] : '127.0.0.1';
                            ^ missing question mark