List returning incorrect values for associated index positions.what improvements can I make in my current approach?

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An list of given length is given

input array- 4 3 1 2 0
indexes- 0 1 2 3 4

expected o/p- 0 4 9 1 16
my output- 16 4 9 1 0

Ouput Explanation- at 0th index value is 4 so we have to check the value at index 4 and square it which means 0x0=0 , and place the value at 0th index in same array

What I have tried:

Below is what I have tried.Please suggest improvements.

x=[]
for i in range(len(a)):
    x.append(a.index(i)**2)
print(x)

Posted 11-Feb-21 9:52am

Member 15070793

Updated 11-Feb-21 10:04am

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Richard MacCutchan 12-Feb-21 3:44am

Use the insert method to add each square in front of the previous entry.

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OriginalGriff · Answer 1 · 2021-02-11T10:04:00

Read what you wrote:

Ouput Explanation- at 0th index value is 4 so we have to check the value at index 4 and square it which means 0x0=0 , and place the value at 0th index in same array

So do that: get the value at the loop variable index, and use that value as an index into the array - then square that value and store back in the array using the loop variable as an index again.

All your code does is get the value at the look variable index, square it, and store that in a different array.